[转]BZOJ4259 残缺的字符串 FFT

转自:https://www.cnblogs.com/clrs97/p/4814499.html

 1 #include<cstdio>
 2 #include<cmath>
 3 #include<algorithm>
 4 #define N 1048576
 5 using namespace std;
 6 char sa[N],sb[N];int n,m,i,j,k,a[N],b[N],ans,q[N];
 7 struct comp{
 8   double r,i;comp(double _r=0,double _i=0){r=_r;i=_i;}
 9   comp operator+(const comp&x){return comp(r+x.r,i+x.i);}
10   comp operator-(const comp&x){return comp(r-x.r,i-x.i);}
11   comp operator*(const comp&x){return comp(r*x.r-i*x.i,r*x.i+i*x.r);}
12 }A[N],B[N],C[N];
13 const double pi=acos(-1.0);
14 void FFT(comp*a,int n,int t){
15   for(int i=1,j=0;i<n-1;i++){
16     for(int s=n;j^=s>>=1,~j&s;);
17     if(i<j)swap(a[i],a[j]);
18   }
19   for(int d=0;(1<<d)<n;d++){
20     int m=1<<d,m2=m<<1;
21     double o=pi/m*t;comp _w(cos(o),sin(o));
22     for(int i=0;i<n;i+=m2){
23       comp w(1,0);
24       for(int j=0;j<m;j++){
25         comp &A=a[i+j+m],&B=a[i+j],t=w*A;
26         A=B-t;B=B+t;w=w*_w;
27       }
28     }
29   }
30   if(t==-1)for(int i=0;i<n;i++)a[i].r/=n;
31 }
32 int main(){
33   scanf("%d%d%s%s",&m,&n,sa,sb);
34   for(i=0,j=m-1;i<j;i++,j--)swap(sa[i],sa[j]);
35   for(i=0;i<m;i++)if(sa[i]!='*')a[i]=sa[i]-'a'+1;
36   for(i=0;i<n;i++)if(sb[i]!='*')b[i]=sb[i]-'a'+1;
37   for(k=1;k<n+m;k<<=1);
38   for(i=0;i<k;i++)A[i]=comp(a[i]*a[i]*a[i],0),B[i]=comp(b[i],0);
39   for(FFT(A,k,1),FFT(B,k,1),i=0;i<k;i++)C[i]=C[i]+A[i]*B[i];
40   for(i=0;i<k;i++)A[i]=comp(a[i],0),B[i]=comp(b[i]*b[i]*b[i],0);
41   for(FFT(A,k,1),FFT(B,k,1),i=0;i<k;i++)C[i]=C[i]+A[i]*B[i];
42   for(i=0;i<k;i++)A[i]=comp(a[i]*a[i],0),B[i]=comp(b[i]*b[i],0);
43   for(FFT(A,k,1),FFT(B,k,1),i=0;i<k;i++)C[i]=C[i]-A[i]*B[i]*comp(2,0);
44   FFT(C,k,-1);
45   for(i=m-1;i<n;i++)if(C[i].r<0.5)q[++ans]=i-m+2;
46   for(printf("%d\n",ans),i=1;i<ans;i++)printf("%d ",q[i]);
47   if(ans)printf("%d",q[ans]);
48   return 0;
49 }

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转载自www.cnblogs.com/aseer/p/8968537.html