PAT甲级推荐做题顺序按照19年9月4日通过率排序

试题编号 通过率
1113 0.63%
1120 0.62%
1008 0.59%
1064 0.58%
1099 0.57%
1094 0.55%
1092 0.54%
1011 0.53%
1083 0.51%
1102 0.51%
1027 0.50%
1054 0.50%
1127 0.49%
1051 0.47%
1056 0.47%
1125 0.47%
1020 0.46%
1130 0.46%
1134 0.46%
1140 0.46%
1155 0.46%
1006 0.45%
1115 0.45%
1030 0.44%
1053 0.44%
1086 0.44%
1138 0.44%
1036 0.43%
1066 0.43%
1114 0.43%
1142 0.43%
1146 0.43%
1041 0.42%
1058 0.42%
1106 0.42%
1050 0.41%
1084 0.41%
1090 0.41%
1124 0.41%
1147 0.41%
1042 0.40%
1116 0.40%
1037 0.39%
1063 0.39%
1079 0.39%
1123 0.39%
1128 0.39%
1076 0.38%
1107 0.38%
1148 0.38%
1149 0.38%
1031 0.37%
1045 0.37%
1049 0.37%
1004 0.36%
1119 0.36%
1121 0.36%
1019 0.35%
1043 0.35%
1062 0.35%
1071 0.35%
1087 0.35%
1109 0.35%
1154 0.35%
1005 0.34%
1028 0.34%
1070 0.34%
1093 0.34%
1129 0.34%
1150 0.34%
1059 0.33%
1073 0.33%
1098 0.33%
1118 0.33%
1013 0.32%
1038 0.32%
1097 0.32%
1104 0.32%
1105 0.32%
1122 0.32%
1133 0.32%
1022 0.31%
1023 0.31%
1039 0.31%
1040 0.31%
1069 0.31%
1091 0.31%
1136 0.31%
1034 0.30%
1035 0.30%
1044 0.30%
1048 0.30%
1088 0.30%
1089 0.30%
1100 0.30%
1145 0.30%
1046 0.29%
1081 0.29%
1103 0.29%
1132 0.29%
1003 0.28%
1009 0.28%
1024 0.28%
1033 0.28%
1068 0.28%
1074 0.28%
1144 0.28%
1025 0.27%
1032 0.27%
1065 0.27%
1067 0.27%
1111 0.27%
1015 0.26%
1021 0.26%
1047 0.26%
1057 0.26%
1082 0.26%
1085 0.26%
1108 0.26%
1135 0.26%
1137 0.26%
1001 0.25%
1012 0.25%
1018 0.25%
1095 0.25%
1110 0.25%
1112 0.25%
1141 0.25%
1151 0.25%
1017 0.24%
1072 0.24%
1078 0.24%
1096 0.24%
1152 0.24%
1080 0.23%
1101 0.23%
1117 0.23%
1126 0.23%
1131 0.23%
1143 0.23%
1060 0.22%
1061 0.22%
1002 0.21%
1014 0.21%
1016 0.21%
1052 0.21%
1055 0.21%
1077 0.21%
1075 0.20%
1153 0.20%
1007 0.19%
1139 0.18%
1026 0.16%
1010 0.11%
1029 0.10%
	string s;
	ifstream cin("PATLOG.txt");
	map<double,vector<int> > M;
	while(getline(cin,s)){
		double d;
		int i;
		sscanf(s.substr(s.find_last_of('\t')).c_str(),"%lf",&d);
		sscanf(s.c_str(),"%d",&i);
		M[d].push_back(i);
	} 
	for(auto it=M.rbegin();it!=M.rend();++it){
		vector<int> &v=it->second;
		sort(v.begin(),v.end());
		double d= it->first;
		for(int i=0;i<v.size();++i){
			printf("| %d | %.2f%%|\n",v[i],d);
		}
	}
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转载自blog.csdn.net/best335/article/details/100532164