1281.整数的各位积和之差
题目描述:
给你一个整数 n,请你帮忙计算并返回该整数「各位数字之积」与「各位数字之和」的差。
示例 1:
输入:n = 234
输出:15
解释:
各位数之积 = 2 * 3 * 4 = 24
各位数之和 = 2 + 3 + 4 = 9
结果 = 24 - 9 = 15
示例 2:
输入:n = 4421
输出:21
解释:
各位数之积 = 4 * 4 * 2 * 1 = 32
各位数之和 = 4 + 4 + 2 + 1 = 11
结果 = 32 - 11 = 21
提示:
1 <= n <= 10^5
题解1:
输的范围为1~100000,计算每一位的值求和与积,最后求积和之差
class Solution {
public int subtractProductAndSum(int n) {
//计算每一位上的数字
int shiwan = n/100000;
int wan = n%100000/10000;
int qian = n%10000/1000;
int bai = n%1000/100;
int shi = n%100/10;
int ge = n%10;
//求和
int sum = shiwan+wan+qian+bai+shi+ge;
//求积
int ji = 1;
if(shiwan!=0){
ji = shiwan*wan*qian*bai*shi*ge;
}else if(wan!=0){
ji = wan*qian*bai*shi*ge;
}else if(qian!=0){
ji = qian*bai*shi*ge;
}else if(bai!=0){
ji = bai*shi*ge;
}else if(shi!=0){
ji = shi*ge;
}else{
ji = ge;
}
//返回差值
return ji-sum;
}
}
题解1改进:
利用循环改进题解1
class Solution {
public int subtractProductAndSum(int n) {
int ji = 1;
int sum = 0;
while(n!=0){
ji *=n%10;
sum +=n%10;
n/=10;
}
return ji-sum;
}
}