题目
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/ti-huan-kong-ge-lcof
解法一:使用Python的replace()函数。replace()语法:str.replace(old,new[,max]),将字符串old替换成new,替换次数不超过max次
class Solution:
def replaceSpace(self, s: str) -> str:
return s.replace(" ","%20")
解法二:将字符串s转换成列表,将列表中的空格替换为“%20”,使用join()拼接字符串,返回拼接后的字串,str.join(sequence),sequence为要连接的字符串序列,按照指定格式拼接
class Solution:
def replaceSpace(self, s: str) -> str:
arr = [str(x) for x in s]
for i in range(len(arr)):
if arr[i]==" ":
arr[i] = "%20"
return ''.join(arr)
解法三:将字符串s转换成列表,将列表中的空格替换成“%20”,使用“+”号拼接字符串返回拼接后的字符串
class Solution:
def replaceSpace(self, s: str) -> str:
arr = [str(x) for x in s]
for i in range(len(arr)):
if arr[i] == " ":
arr[i] = "%20"
str1 = ""
for i in arr:
str1 += i
return str1