【CODE】Insert Interval

57. Insert Interval

Hard

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Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:

Input: intervals = [[1,3],[6,9]], newInterval = [2,5]
Output: [[1,5],[6,9]]

Example 2:

Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]

Output: [[1,2],[3,10],[12,16]]
Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10]

NOTE: input types have been changed on April 15, 2019. Please reset to default code definition to get new method signature.

class Solution {
public:
    bool overlap(vector<int> a,vector<int> b){
        if(a[0]>b[b.size()-1]) return false;
        if(a[a.size()-1]<b[0]) return false;
        return true;
    }
    vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {
        vector<vector<int> > res;
        int i=0,flag=0;
        for(i=0;i<intervals.size();i++){
            if(overlap(intervals[i],newInterval)){
                newInterval={min(intervals[i][0],newInterval[0]),max(intervals[i][1],newInterval[1])};
                cout<<"overlap "<<newInterval[0]<<" "<<newInterval[1]<<endl;
            }else{
                cout<<"no overlap "<<newInterval[0]<<" "<<newInterval[1]<<endl;
                if(intervals[i][1]<newInterval[0]) res.push_back(intervals[i]);
                else{
                    res.push_back(newInterval);flag=1;
                    break;
                }
            }
        }
        if(flag==0) res.push_back(newInterval);
        if(flag==1){
            cout<<i<<endl;
            while(i<intervals.size()){
                res.push_back(intervals[i++]);
            }
        }
        return res;
    }
};
  • Runtime: 20 ms, faster than 49.77% of C++ online submissions for Insert Interval.
  • Memory Usage: 13.3 MB, less than 5.00% of C++ online submissions for Insert Interval.
  • Next challenges:
  • Merge Intervals
  • Range Module
  • 合并所有的覆盖区间
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转载自blog.csdn.net/Li_Jiaqian/article/details/102821821