We are given two strings, A
and B
.
A shift on A
consists of taking string A
and moving the leftmost character to the rightmost position. For example, if A = 'abcde'
, then it will be 'bcdea'
after one shift on A
. Return True
if and only if A
can become B
after some number of shifts on A
.
Example 1: Input: A = 'abcde', B = 'cdeab' Output: true Example 2: Input: A = 'abcde', B = 'abced' Output: false
Note:
A
andB
will have length at most100
.
题目是判断字符串A见过旋转,能否变成字符串B。
思路是把两个字符串A首位连起来,看字符串B是否是它的子串
class Solution {
public:
bool rotateString(string A, string B) {
return (A+A).find(B)<A.length();
}
};