题目描述:
请实现一个函数,将一个字符串中的每个空格替换成“%20”。例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy。
思路:
字符串元素的替换,只需要找到元素为空格的索引,然后用%20替换即可。
AC代码
逐字符的寻找空格替换
# -*- coding:utf-8 -*-
class Solution:
# s 源字符串
def replaceSpace(self, s):
# write code here
s = list(s)
for i in range(len(s)):
if s[i] == ' ':
s[i] = '%20'
return ''.join(s)
一行代码解决
# -*- coding:utf-8 -*-
class Solution:
# s 源字符串
def replaceSpace(self, s):
# write code here
return '%20'.join(s.split(' '))