树和图(leetcode) :中序遍历二叉树

给定一个二叉树,返回它的中序 遍历。

示例:

输入: [1,null,2,3]
   1
    \
     2
    /
   3

输出: [1,3,2]

进阶: 递归算法很简单,你可以通过迭代算法完成吗?

解答(C++):

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<int> inorderTraversal(TreeNode* root) {
        std::vector<int> vec;
        std::stack<TreeNode*> st;
        TreeNode* p = root;
        while (!st.empty() || p) {
            while (p) {
                st.push(p);
                p = p->left;
            }
            
            if (!st.empty()) {
                p = st.top();
                st.pop();
                vec.push_back(p->val);
                p = p->right;
            }
        }
        return vec;
        
    }
};

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转载自www.cnblogs.com/vczf/p/12508586.html