CodeForces-842A

感觉自己傻了，这么一道题竟然用n2的循环嵌套来做（我承认刚开始没有想到化简复杂度。。。），言归正题
a/b可能的最大值是r/x， 可能的最小值是l/y
即l<=k*j且r>=k*x为基本条件

A. Kirill And The Game

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Kirill plays a new computer game. He came to the potion store where he can buy any potion. Each potion is characterized by two integers — amount of experience and cost. The efficiency of a potion is the ratio of the amount of experience to the cost. Efficiency may be a non-integer number.

For each two integer numbers a and b such that l ≤ a ≤ r andx ≤ b ≤ y there is a potion with experiencea and costb in the store (that is, there are(r - l + 1)·(y - x + 1) potions).

Kirill wants to buy a potion which has efficiency k. Will he be able to do this?

Input

First string contains five integer numbers l,r,x,y,k (1 ≤ l ≤ r ≤ 10⁷,1 ≤ x ≤ y ≤ 10⁷,1 ≤ k ≤ 10⁷).

Output

Print "YES" without quotes if a potion with efficiency exactlyk can be bought in the store and "NO" without quotes otherwise.

You can output each of the letters in any register.

Examples

Input

1 10 1 10 1

Output

YES

Input

1 5 6 10 1

Output

NO
 

#include
 #include
 #include
 #include
 using namespace std; 
 int main()
 {
	long long l, r, x, y, k;
	cin >>l>>r>>x>>y>>k;
	int flag = 0;
	if (l > y*k || r < x*k)
	{
		cout<<"NO"<= l && j*k <= r)	//判断j*k是否在区间（l， r）内 
		{
			flag = 1;
			break;
		}
	}
	if(flag == 1)
	{
		cout<<"YES"<