plsql Oracle分组函数之ROLLUP

本文通过演示给出Oracle ROLLUP分组函数的用法，体验一下Oracle在统计查询领域中的函数魅力。ROLLUP分组函数可以理解为Group By分组函数封装后的精简用法，这里同时给出ROLLUP的Group By的改写思路。

1.初始化实验坏境
1）创建测试表group_test
SECOOLER@ora11g> create table group_test (group_id int, job varchar2(10), name varchar2(10), salary int);

Table created.

2）初始化数据
insert into group_test values (10,'Coding',    'Bruce',1000);
insert into group_test values (10,'Programmer','Clair',1000);
insert into group_test values (10,'Architect', 'Gideon',1000);
insert into group_test values (10,'Director',  'Hill',1000);

insert into group_test values (20,'Coding',    'Jason',2000);
insert into group_test values (20,'Programmer','Joey',2000);
insert into group_test values (20,'Architect', 'Martin',2000);
insert into group_test values (20,'Director',  'Michael',2000);

insert into group_test values (30,'Coding',    'Rebecca',3000);
insert into group_test values (30,'Programmer','Rex',3000);
insert into group_test values (30,'Architect', 'Richard',3000);
insert into group_test values (30,'Director',  'Sabrina',3000);

insert into group_test values (40,'Coding',    'Samuel',4000);
insert into group_test values (40,'Programmer','Susy',4000);
insert into group_test values (40,'Architect', 'Tina',4000);
insert into group_test values (40,'Director',  'Wendy',4000);

commit;

3）初始化之后的数据情况如下：
SECOOLER@ora11g> set pages 100
SECOOLER@ora11g> select * from group_test;

  GROUP_ID JOB        NAME           SALARY
---------- ---------- ---------- ----------
        10 Coding     Bruce            1000
        10 Programmer Clair            1000
        10 Architect  Gideon           1000
        10 Director   Hill             1000
        20 Coding     Jason            2000
        20 Programmer Joey             2000
        20 Architect  Martin           2000
        20 Director   Michael          2000
        30 Coding     Rebecca          3000
        30 Programmer Rex              3000
        30 Architect  Richard          3000
        30 Director   Sabrina          3000
        40 Coding     Samuel           4000
        40 Programmer Susy             4000
        40 Architect  Tina             4000
        40 Director   Wendy            4000

16 rows selected.

2.先看一下普通分组的效果：对group_id进行普通的group by操作---按照小组进行分组
SECOOLER@ora11g> select group_id,sum(salary) from group_test group by group_id;

  GROUP_ID SUM(SALARY)
---------- -----------
        30       12000
        20        8000
        40       16000
        10        4000

3.对group_id进行普通的roolup操作---按照小组进行分组，同时求总计

rollup和group by的区别是：rollup最后会求总计

SECOOLER@ora11g> select group_id,sum(salary) from group_test group by rollup(group_id);

  GROUP_ID SUM(SALARY)
---------- -----------
        10        4000
        20        8000
        30       12000
        40       16000
                 40000

  使用Group By语句翻译一下上面的SQL语句如下（union all一个统计所有数据的行）：
SECOOLER@ora11g> select group_id,sum(salary) from group_test group by group_id
  2  union all

  3  select null, sum(salary) from group_test  

#总计那一行，第一列group_id是空的，故select null,sum...

  4  order by 1;  #按第1列排序，即按group_id排序

  GROUP_ID SUM(SALARY)
---------- -----------
        10        4000
        20        8000
        30       12000
        40       16000
                 40000

4.再看一个rollup两列的情况
SECOOLER@ora11g> select group_id,job,sum(salary) from group_test group by rollup(group_id, job);

#rollup(group_id,job)按group_id,job分组且最后求总计(按group_id,job后每个组的总计)

  GROUP_ID JOB        SUM(SALARY)
---------- ---------- -----------
        10 Coding            1000
        10 Director          1000
        10 Architect         1000
        10 Programmer        1000
        10                   4000
        20 Coding            2000
        20 Director          2000
        20 Architect         2000
        20 Programmer        2000
        20                   8000
        30 Coding            3000
        30 Director          3000
        30 Architect         3000
        30 Programmer        3000
        30                  12000
        40 Coding            4000
        40 Director          4000
        40 Architect         4000
        40 Programmer        4000
        40                  16000
                            40000

21 rows selected.

上面的SQL语句该如何使用Group By进行翻译呢？
答案如下：
SECOOLER@ora11g> select group_id,job,sum(salary) from group_test group by group_id, job
  2  union all
  3  select group_id,null,sum(salary) from group_test group by group_id
  4  union all
  5  select null,null,sum(salary) from group_test
  6  order by 1,2; #按第一列和第2列排序即(group_id,job)

#第一个union all:select group_id,null,sum(salary) from group_test group by group_id 

它是相当于group_id分组后每一个小项汇总，它的group_id是有值(下面的10)，job没值，故select语句中select 

group_id,null,

#第二个union all:是最后一行汇总，它的group_id,job全是空的，故select null,null,sum...

  GROUP_ID JOB        SUM(SALARY)
---------- ---------- -----------
        10 Architect         1000
        10 Coding            1000
        10 Director          1000
        10 Programmer        1000
        10                   4000
        20 Architect         2000
        20 Coding            2000
        20 Director          2000
        20 Programmer        2000
        20                   8000
        30 Architect         3000
        30 Coding            3000
        30 Director          3000
        30 Programmer        3000
        30                  12000
        40 Architect         4000
        40 Coding            4000
        40 Director          4000
        40 Programmer        4000
        40                  16000
                            40000

21 rows selected.

5.补充一步，体验一下GROUPING函数的效果

grouping只是这个值在这一行中是原来的值，还是汇总的值，若是原来的值，则为0，若是汇总后的值，则为1.

下面的红色字体：10 0 1 4000为例，此条数据，group(group_ID)还是原来10，故为0;grouping(JOB)这行的job

是空值，不是前面的Coding之类的，故为1,因为它是汇总小计列。最后一行总计也是类似。

直接看效果就OK啦：
SECOOLER@ora11g> select group_id,job,grouping(GROUP_ID),grouping(JOB),sum(salary) from group_test group by rollup(group_id, job);

  GROUP_ID JOB        GROUPING(GROUP_ID) GROUPING(JOB) SUM(SALARY)
---------- ---------- ------------------ ------------- -----------
        10 Coding                      0             0        1000
        10 Director                    0             0        1000
        10 Architect                   0             0        1000
        10 Programmer                  0             0        1000
        10                             0             1        4000
        20 Coding                      0             0        2000
        20 Director                    0             0        2000
        20 Architect                   0             0        2000
        20 Programmer                  0             0        2000
        20                             0             1        8000
        30 Coding                      0             0        3000
        30 Director                    0             0        3000
        30 Architect                   0             0        3000
        30 Programmer                  0             0        3000
        30                             0             1       12000
        40 Coding                      0             0        4000
        40 Director                    0             0        4000
        40 Architect                   0             0        4000
        40 Programmer                  0             0        4000
        40                             0             1       16000
                                       1             1       40000

21 rows selected.

  看出来什么效果了么？
  有的同学还是没有看出来，小小的解释一下：
  如果显示“1”表示GROUPING函数对应的列（例如JOB字段）是由于ROLLUP函数所产生的空值对应的信息，即对此列进行汇总计算后的结果。

  如果显示“0”表示此行对应的这列参未与ROLLUP函数分组汇总活动。

补充例题：自己解释如下

select sum(salary),department,bonus,group_id() from employees
where bonus > 100
group by department,
rollup(department,bouns);

应该是这样的：group_id()去重，rollup(department,bonus)是按department,bonus分组后汇总(24000)
sum(salary)  department  bonus  
4000		 10		     200
8000         20	         400
12000        30          700
24000


SELECT SUM(salary), department, bonus, GROUP_ID()
FROM employees
WHERE bonus > 100
GROUP BY department,
ROLLUP (department, bonus)
HAVING GROUP_ID() < 1;
注意：HAVING GROUP_ID() < 1 #是指所有值都是非空值，若是空值是为0，非空值为1，group_id是按二进制来计算的
例如：GROUP_ID(department,bonus),deparment的值为非空，是1，非空为0。 假如deparment 为非空(1)，bonus为空(0)
则GROUP_ID(department,bonus)为2（10转二进制为2）.