获取url地址？后的参数值

获取URL参数方法

// 获取url拼接参数值
function GetRequest() {
	var url = location.search; // 获取url中"?"符后的字串
	var theRequest = new Object();
	if (url.indexOf("?") != -1) {
		var str = url.substr(1);
		strs = str.split("&");
		for (var i = 0; i < strs.length; i++) {
			theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
		}
	}
	return theRequest;
}

例：src="/itsm/systemmanager/noticemanager/EnterpriseNumSendMessage.html?geogId=100001&tabId=tab_problem”

var geogId = GetRequest().geogId;
//geogId=100001