MySQL生成整年日期表（不用函数和存储过程）

1.创建小数据表 0-9

-- 创建小数据表 0-9
DROP TABLE IF EXISTS aa_numbers_small;
CREATE TABLE aa_numbers_small(
    number INT);
--插入数据
INSERT INTO aa_numbers_small VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9);
SELECT * FROM aa_numbers_small;

2.创建大数据表 0-10000

DROP TABLE IF EXISTS aa_numbers;
CREATE TABLE aa_numbers(number BIGINT);
INSERT INTO aa_numbers
SELECT thousand.number*1000+hundred.number*100+ten.number*10+ones.number
FROM aa_numbers_small thousand, aa_numbers_small hundred, aa_numbers_small ten, aa_numbers_small ones
LIMIT 1000000;
SELECT * FROM aa_numbers;

3. 创建时间维表

DROP TABLE IF EXISTS aa_date;
CREATE TABLE aa_date(
    date_id          BIGINT PRIMARY KEY,
    DATE             DATE NOT NULL,
    DAY              CHAR(10),
    day_of_week      INT,
    day_of_month     INT,
    day_of_year      INT,
    previous_day     DATE NOT NULL DEFAULT '0000-00-00',
    next_day         DATE NOT NULL DEFAULT '0000-00-00',
    weekend          CHAR(10) NOT NULL DEFAULT "Weekday",
    week_of_year     CHAR(2),
    MONTH            CHAR(10),
    month_of_year    CHAR(2),
    quarter_of_year INT,
    YEAR             INT,
    UNIQUE KEY `date` (`date`));

SELECT * FROM aa_date;

4. 填充数据

这里以2020年为例

INSERT INTO aa_date(date_id, DATE)
SELECT number, DATE_ADD('2020-01-01', INTERVAL number DAY)
FROM aa_numbers
WHERE DATE_ADD('2020-01-01', INTERVAL number DAY) BETWEEN '2020-01-01' AND '2020-12-31'
ORDER BY number;

5.根据日期update其他列数据

UPDATE aa_date SET
DAY             = DATE_FORMAT( DATE, "%W" ),
day_of_week     = DAYOFWEEK(DATE),
day_of_month    = DATE_FORMAT( DATE, "%d" ),
day_of_year     = DATE_FORMAT( DATE, "%j" ),
previous_day    = DATE_ADD(DATE, INTERVAL -1 DAY),
next_day        = DATE_ADD(DATE, INTERVAL 1 DAY),
weekend         = IF( DATE_FORMAT( DATE, "%W" ) IN ('Saturday','Sunday'), 'Weekend', 'Weekday'),
week_of_year    = DATE_FORMAT( DATE, "%V" ),
MONTH           = DATE_FORMAT( DATE, "%M"),
month_of_year   = DATE_FORMAT( DATE, "%m"),
quarter_of_year = QUARTER(DATE),
YEAR            = DATE_FORMAT( DATE, "%Y" );