208.实现Trie

题目描述:

实现一个 Trie (前缀树),包含 insert, search, 和 startsWith 这三个操作。

示例:

Trie trie = new Trie();

trie.insert("apple");
trie.search("apple"); // 返回 true
trie.search("app"); // 返回 false
trie.startsWith("app"); // 返回 true
trie.insert("app");
trie.search("app"); // 返回 true
说明:

你可以假设所有的输入都是由小写字母 a-z 构成的。
保证所有输入均为非空字符串。

思想:

https://leetcode-cn.com/problems/implement-trie-prefix-tree/solution/trie-tree-de-shi-xian-gua-he-chu-xue-zhe-by-huwt/

代码:

class Trie {
private:
    bool isEnd;
    Trie *next[26];
public:
    /** Initialize your data structure here. */
    Trie() {
        isEnd = false;
        memset(next,0,sizeof(next));
    }
    
    /** Inserts a word into the trie. */
    void insert(string word) {
        Trie* node = this;
        for(char c:word){
            if(node->next[c-'a']==NULL)
                node->next[c-'a']=new Trie;
            node = node->next[c-'a'];
        }
        node->isEnd=true;
    }
    
    /** Returns if the word is in the trie. */
    bool search(string word) {
        Trie* node = this;
        for(char c:word){
            node = node->next[c-'a'];
            if(node == NULL)
                return false;
        }
        return node->isEnd;
    }
    
    /** Returns if there is any word in the trie that starts with the given prefix. */
    bool startsWith(string prefix) {
        Trie* node = this;
        for(char c:prefix){
            node = node->next[c-'a'];
            if(node == NULL)
                return false;
        }
        return true;
    }
};

/**
 * Your Trie object will be instantiated and called as such:
 * Trie* obj = new Trie();
 * obj->insert(word);
 * bool param_2 = obj->search(word);
 * bool param_3 = obj->startsWith(prefix);
 */

猜你喜欢

转载自www.cnblogs.com/thefatcat/p/12798185.html
今日推荐