13-简单-罗马数字转整数

在这里插入图片描述
踩了个坑,这里学到了字符串存储是从左往右开始存储的

int romanToInt(char* s) {
    int l_temp = 0;
    while (*s) {
        switch (*s) {
        case 'I':
            if (('X' == *(s + 1))|| ('V' == *(s + 1))){
                l_temp -= 1;
            }else{
                l_temp += 1;
            }
            break;
        case 'V':
            l_temp += 5;
            break;
        case 'X':
            if (('C' == *(s + 1)) || ('L' == *(s + 1))){
                l_temp -= 10;
            }else{
                l_temp += 10;
            }
            break;
        case 'L':
            l_temp += 50;
            break;
        case 'C':
            if (('D' == *(s + 1)) || ('M' == *(s + 1))){
                temp -= 100;
            }else{
                temp += 100;
            }
            break;
        case 'D':
            l_temp += 500;
            break;
        case 'M':
            l_temp += 1000;
            break;

        default:
            break;
        }
        // printf("string = %c\r\n", *s);
        s++;
    }

    return l_temp;
}

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转载自blog.csdn.net/lala0903/article/details/107512092
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