797. All Paths From Source to Target

/*
Given a directed, acyclic graph of N nodes.  Find all possible paths from node 0 to node N-1, and return them in any order.

The graph is given as follows:  the nodes are 0, 1, ..., graph.length - 1.  graph[i] is a list of all nodes j for which the edge (i, j) exists.

Example:
Input: [[1,2], [3], [3], []]
Output: [[0,1,3],[0,2,3]]
Explanation: The graph looks like this:
0--->1
|    |
v    v
2--->3
There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.

Note:

    The number of nodes in the graph will be in the range [2, 15].
    You can print different paths in any order, but you should keep the order of nodes inside one path.



*/

class Solution {
    public List<Integer> column;
    
    public List<List<Integer>> allPathsSourceTarget(int[][] graph) {
        List<List<Integer>> g = new ArrayList<List<Integer>>();
        List<Integer> path = new ArrayList<Integer>();
        path.add(0);
        DFS(graph,0,g,path);
        return g;
    }
    
    public void DFS(int[][] graph, Integer node, List<List<Integer>> g, List<Integer> path){
        if(node==graph.length-1){
            g.add(new ArrayList<Integer>(path));
            return;
        }
        
        for(int nextNode:graph[node]){
            path.add(nextNode);
            DFS(graph, nextNode, g, path);
            path.remove(path.size()-1);
        }
    }
}

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转载自blog.csdn.net/lee18254290736/article/details/80483530