codeforces Round #668 (Div. 2) 1405A Permutation Forgery - 代码天地

codeforces Round #668 (Div. 2) 1405A Permutation Forgery

其他 2020-10-29 10:07:32 阅读次数: 0

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转载自blog.csdn.net/lmmmmmmmmmmmmmmm/article/details/108463088

codeforces Round #668 (Div. 2) 1405A Permutation Forgery

Codeforces Round #668 (Div. 2)

codeforces Round #668 (Div. 2) 1405C Balanced Bitstring

codeforces Round #668 (Div. 2) 1405B Array Cancellation

Codeforces Round #668 (Div. 2)A-D题解

Codeforces Round #668 (Div. 2)（A-D详解)

Codeforces Round #514 (Div. 2) B. Forgery

Codeforces Round #514 (Div. 2), problem: (B) Forgery

Codeforces Round #514 (Div. 2) B - Forgery

Codeforces Round #514 (Div. 2) B. Forgery （暴力？）

Codeforces Round #668 (Div. 1)

Codeforces Round #668 (Div. 1)

Codeforces Round #668 (Div. 1) 题解

Codeforces Round #668 (Div. 1) Solution

Codeforces 1405B #668Div2B

Codeforces Round #309 (Div. 2) D. Kyoya and Permutation

Codeforces Round #144 (Div. 2) A. Perfect Permutation

Codeforces Round #623 (Div. 2）C. Restoring Permutation

Codeforces Round #514 (Div. 2)A. Cashier,B. Forgery,C. Sequence Transformation

Codeforces Round #668(Div.2) A,B,C,D

Codeforces Round #668 A~D题解(div2)

Codeforces Round #668 (Div. 2)D. Tree Tag(树形DP树的直径 + 博弈论)

Educational Codeforces Round 81 (Rated for Div. 2) E - Permutation Separation (线段树+思维）

E. Permutation Separation,Educational Codeforces Round 81 (Rated for Div. 2),线段树

E. Permutation Separation,Educational Codeforces Round 81 (Rated for Div. 2),线段树

Educational Codeforces Round 81 (Rated for Div. 2) E. Permutation Separation(线段树)

Codeforces Round #463 (Div. 1 + Div. 2, combined) C. Permutation Cycle ---- 思维+扩展欧几里得

Codeforces Round #598 (Div. 3) B. Minimize the Permutation

Codeforces Round #615 (Div. 3) E. Obtain a Permutation

Codeforces Round #598 (Div. 3) B Minimize the Permutation

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