SQL server，Oracle循环插入百万数据

压测时常需要往数据库插入大量数据，下面是我往两个数据库插入数据时用的脚本

SQL server

declare @maxSum int,
        @lid nvarchar(64), -- 'lid'为表id
        @cid int,
        @userid nvarchar(64),
        @oper_time nvarchar(26),
        @oper_type nvarchar(10),
		@oper_host nvarchar(64),
		@permission nvarchar(100),
		@status nvarchar(10),
		@detalls nvarchar(max),
		@version int
set @maxSum=1
set @cid='1'
set @userid='1'
set @oper_time='2020-10-26 12:15:07.000761'
set @oper_type='7'
set @oper_host='127.0.0.1'
set @permission='system'
set @status='0'
set @detalls='{"msg":"Login for User:admin.","logBeans":null}'
set @version='0'
begin tran
while @maxSum<200000
begin
set @lid='LID'+convert(nvarchar,@maxSum) -- id加'LID'前缀方便识别
   insert into T_AT_LOG (LID,CID,USERID,OPER_TIME,OPER_TYPE,OPER_HOST,PERMISSION,STATUS,DETAILS,VERSION) 
                 values(@lid,@cid,@userid,@oper_time,@oper_type,@oper_host,@permission,@status,@detalls,@version)
   set @maxSum=@maxSum+1

end
commit

数据要分批Commit，这里我是单次20万笔，数据库是无法支撑单次几百万笔Commit的。
单笔耗时28秒

这脚本效率不是很满意，有更高效率的脚本欢迎在评论区分享

Oracle

DECLARE
   a number(30) := 0;
BEGIN
   for i in 1 .. 200000 loop
      INSERT INTO T_AT_LOG(LID,CID,USERID,OPER_TIME,OPER_TYPE,OPER_HOST,PERMISSION,STATUS,DETAILS,VERSION) 
                    VALUES(i,'1','1','2020-10-13 10:25:38.000176','8','127.0.0.1','system','0','{"msg":"Login for User:admin.","logBeans":null}','0');
   end loop;
   commit;
END;

这里一样是分批Commit
单笔耗时33秒