纵横字谜的答案(Crossword Answers, ACM/ICPC World Finals 1994, UVa232)原题链接

原题链接
主要题意呢就是竞赛书上的那个意思,输入输出格式看一下原题链接就行了
先输入c,r接着给出c行r列的表

#include<bits/stdc++.h>

using namespace std;

char a[10][10];
int judge[10][10];

int main()
{
    
    
	int c, r;
	int sum = 1;
	while (1)
	{
    
    
		
		cin >> c >> r;
		if (c = 0)
			break;
		cin >> c >> r;
		for (int i = 0; i < c; i++)
			for (int j = 0; j < r; j++)
			{
    
    
				cin >> a[i][j];
				if (a[i][j] == '*')
					judge[i][j] = -1;
			}
		int ans = 1;
		for (int i = 0; i < c; i++)
			for (int j = 0; j < r; j++)
			{
    
    
				if ((i == 0 || j == 0) && judge[i][j] != -1)
					judge[i][j] = ans;
				ans++;
			}
		cout << "puzzle #" << sum << endl;
		cout << "Across" << endl;
		for(int i=0;i<c;i++)
			for (int j = 0; j < r; j++)
			{
    
    
				for (int k = j; k < r; k++)
				{
    
    
					if (judge[i][j] == -1)
						break;
					else
					{
    
    
						if (k == j)
							cout << "	" << judge[i][k] << ".";
						cout << a[i][k];
					}
					if (k == r - 1)
						cout << endl;
				}
				
			}
		for (int i = 0; i < r; i++)
			for (int j = 0; j < c; j++)
			{
    
    
				for (int k = j; k < c; k++)
				{
    
    
					if (judge[i][j] == -1)
						break;
					else
					{
    
    
						if (k == j)
							cout << "	" << judge[k][i] << ".";
						cout << a[k][i];
					}
					if (k == c - 1)
						cout << endl;
				}

			}

		sum++;
	}
	

}

这是我自己写的,可能不对呜呜

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转载自blog.csdn.net/qq_46264636/article/details/105032216