PAT 乙级 1002 写出这个数 (20分)---【字符串，数组】

思路：

	1.因为输入int数字是<=100位，用string字符串输入
	2.再循环把每个数字（字符串类型）转换成int类型（-48/‘0’）；与此同时做总和运算sum
	3.写一个字符串数组，存放拼音char str[10][10]/string str[10]
	4.把sum（int）转换成string（to_string(sum)），遍历sum中每位，输出对应下标上的拼音。

代码：

#include<bits/stdc++.h>
using namespace std;

int main(){
    
    
	string s;
	cin>>s;
	int sum=0;
	for(int i = 0; i < s.length();i++){
    
    
		sum=sum+(s[i]-'0');
	} 
	char pinyin[][10]={
    
    "ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
//	string pinyin[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; 
	string num = to_string(sum);
	for(int i = 0; i < num.length(); i++){
    
    
		cout<<pinyin[num[i]-'0'];
		if(i < num.length()-1){
    
    
			cout<<" ";
		}
	}
	return 0;
}