AtCoder Beginner Contest 179
A - Plural Form
#include <bits/stdc++.h>
#define int ll
using namespace std;
typedef long long ll;
const int maxn = 1e5 + 10;
const int mod=998244353;
void solve() {
string s;
cin>>s;
cout<<s<<(s.back()=='s'?"es":"s");
}
signed main() {
int _ = 1;
while (_--) {
solve();
}
return 0;
}
B - Go to Jail
#include <bits/stdc++.h>
#define int ll
using namespace std;
typedef long long ll;
const int maxn = 1e5 + 10;
const int mod=998244353;
void solve() {
int n;
cin>>n;
int flag=0;
for(int i=0;i<n;i++){
int d1,d2;
cin>>d1>>d2;
if(d1==d2) flag++;
else flag=0;
if(flag==3) break;
}
cout<<(flag==3?"Yes":"No");
}
signed main() {
int _ = 1;
while (_--) {
solve();
}
return 0;
}
C - A x B + C
#include <bits/stdc++.h>
#define int ll
using namespace std;
typedef long long ll;
const int maxn=1e5+5;
void solve(){
int n;
cin>>n;
int sum=0;
for(int i=1;i<n;i++) sum+=(n-1)/i;
cout<<sum;
}
signed main() {
int _ = 1;
while (_--) solve();
return 0;
}
D - Leaping Tak
#include <bits/stdc++.h>
#define int ll
using namespace std;
typedef long long ll;
const int maxn = 2e5 + 10;
const int mod = 998244353;
int l[maxn], r[maxn], sum[maxn], dp[maxn];
void solve() {
int n, k;
cin >> n >> k;
for (int i = 1; i <= k; ++i) cin >> l[i] >> r[i];
sum[1] = 1;
for (int i = 2; i <= n; ++i) {
for (int j = 1; j <= k; ++j)
dp[i]=(dp[i]+sum[max(0ll, i-l[j])]-sum[max(0ll, i-r[j]-1)])%mod;
sum[i] = (sum[i - 1] + dp[i]) % mod;
}
cout << (dp[n] + mod) % mod;
}
signed main() {
int _ = 1;
while (_--) solve();
return 0;
}
#include <bits/stdc++.h>
#define int ll
using namespace std;
typedef long long ll;
const int mod = 998244353;
const int maxn = 2e5 + 10;
vector<pair<int,int> >vv;
int tree[maxn * 4];
int lazy[maxn * 4];
int dp[maxn];
void init() {
vv.clear();
}
void pushdown(int t) {
if(lazy[t]==0) return ;
lazy[t << 1] +=lazy[t];
lazy[t<<1]%=mod;
lazy[t << 1 | 1] +=lazy[t];
lazy[t<<1|1]%=mod;
tree[t << 1] +=lazy[t];
tree[t<<1]%=mod;
tree[t << 1|1] += lazy[t];
tree[t<<1|1]%=mod;
lazy[t]=0;
}
int query(int l, int r, int t, int L, int R) {
if (l >= L && r <= R) return tree[t];
if (l > R || r < L) return 0;
int mid = (l + r) >> 1;
int d = 0;
pushdown(t);
if (mid >= L) d = max(d, query(l, mid, t << 1, L, R));
if (mid < R) d = max(d, query(mid + 1, r, t << 1 | 1, L, R));
return d;
}
void update(int l, int r, int t, int L, int R, int d) {
if(L>r||R<l) return ;
if (l >= L && r <= R) lazy[t] += d,lazy[t]%=mod, tree[t]+=d,tree[t]%=mod;
else {
pushdown(t);
int mid = (l + r) >> 1;
if (mid >= L)update(l, mid, t << 1, L, R, d);
if (mid < R) update(mid + 1, r, t << 1 | 1, L, R, d);
}
}
void solve() {
int n,k;
cin>>n>>k;
for (int i = 1; i <= k; ++i) {
int l,r;
cin>>l>>r;
vv.push_back({
l,r});
}
dp[1]=1;
update(1,n,1,1,1,1);
for (int i = 1; i <=n; ++i) {
for (int j = 0; j < vv.size(); ++j) {
pair<int ,int > xx=vv[j];
if(i!=1) dp[i]=query(1,n,1,i,i)%mod;
if(dp[i]!=0) update(1, n, 1, i + xx.first, i + xx.second, dp[i]);
}
}
cout<<dp[n];
}
signed main() {
int _ = 1;
while (_--) {
init();
solve();
}
return 0;
}
E - Sequence Sum
#include <bits/stdc++.h>
#define int ll
using namespace std;
typedef long long ll;
const int maxn = 1e5 + 10;
const int mod = 998244353;
int sum[maxn];
int f[maxn];
void solve() {
int n,x,m;
cin>>n>>x>>m;
int xx=x,ans,bns;
for (int i = 1;; ++i) {
if(!f[xx]) f[xx]=i;
else{
ans=f[xx],bns=i-1;
break;
}
sum[i]=sum[i-1]+xx;
xx=xx*xx%m;
}
int res=sum[min(n,ans-1)];
int len=bns-ans+1;
if(n>ans-1) res+=(sum[bns]-sum[ans-1])*((n-ans+1)/len)+(sum[(n-ans+1)%len+ans-1]-sum[ans-1]);
cout<<res;
}
signed main() {
int _ = 1;
while (_--) solve();
return 0;
}