#include <stdio.h>
int CountDigit( int number, int digit );
int main()
{
int number, digit;
scanf("%d %d", &number, &digit);
printf("Number of digit %d in %d: %d\n", digit, number, CountDigit(number, digit));
return 0;
}
int CountDigit( int number, int digit )
{
int count = 0;
if(number < 0)number = -number;
while(number >= 10)
{
if( number % 10 == digit ) count++;
number = number / 10;
}
if( number % 10 == digit )count++;
return count;
}
(PAT)实现一个统计整数中指定数字的个数的简单函数
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转载自blog.csdn.net/qq_52001969/article/details/112062832
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