数据库查询语句罗列


#1 操作文件夹(库)

create database db1 charset utf8; --指定格式为utf8


show databases; --查看所有的数据库
show create database db1; --查看已经建好的数据库信息

alter database db1 charset gbk; --修改数据库的字符编码

drop database db1;
其他
use database_name; ---使用某个数据库,相当于进入这个数据库(文件夹)
select database(); ---显示当前所在的数据库

#2 操作文件(表)

切换到文件夹下:use db1


create table t1(id int,name char(10))engine=innodb;--增加一个表,后面追加了他的数据引擎
create table t2(id int,name char(10))engine=innodb default charset utf8;--增加一个表,后面追加了他的数据引擎和

show tables;--查看表中的所有表
show create table t1; --查看已有的表的类型和desc功能差不多,就是表先形式不好。

desc t1;---查看表结构

alter table t1 add age int; -----------------给已有的表中添加字段(重点)
列:alter table ti add 添加的名 类型;
alter table t1 modify name char(12); --------修改字段的类型。
rename table 原表名 to 新表名 -------------修改表名
---------------------------------------------------------------
2.修改字段 (以t2表为例)
alter table t2 modify salary int not null; # 更改salary字段的数据类型,并加not null的约束条件。
alter table t2 change salary salaries int; # 更改salary字段的名字为salaries,注意 会改变约束条件,需要的话,需要添加;
其实相当于删除了salary字段,重新创建了一个salaries字段。


drop table t1; --直接删除一个表。

#3 操作文件的一行行内容(记录)

insert into db1.t1 values(1,'egon1'),(2,'egon2'),(3,'egon3');
insert into db1.t1(name) values('egon1'),('egon2'),('egon3');

select * from t1;
select name from t1、、、、、、;
select name,id from t1;

update t1 set name='SB' where id=4;
+ update t1 set name='SB' where name='alex';

delete from t1 where id=4;


#对于清空表记录有两种方式,但是推荐后者
delete from t1;
truncate t1; #当数据量比较大的情况下,使用这种方式,删除速度快



#自增id
create table t5(id int primary key auto_increment,name char(10));
create table t4(id int not null unique,name char(10));

insert into t5(name) values
('egon5'),
('egon6'),
('egon7'),
('egon8'),
('egon9'),
('egon10'),
('egon11'),
('egon12'),
('egon13');

#拷贝表结构
create table t7 select * from t5 where 1=2;
alter table t7 modify id int primary key auto_increment;

insert into t7(name) values
('egon1'),
('egon2'),
('egon3'),
('egon4'),
('egon5'),
('egon6'),
('egon7'),
('egon8'),
('egon9'),
('egon10'),
('egon11'),
('egon12'),
('egon13');


delete from t7 where id=1; #删记录
update t7 set name=''; #修改字段对应的值


-------------------------------------------------------------------------------
select sex, concat('(平均工资:',max(salary),')') 男员工的平均薪资 from em group by sex;
concat('(平均工资:',max(salary),')')
 
2-权限问题
#创建用户
create user 'xbb'@'localhost' identified by '123';


#insert,delete,update,select
#级别1:对所有库,下的所有表,下的所有字段
grant select on *.* to 'lin1'@'localhost' identified by '123';

#级别2:对db1库,下的所有表,下的所有字段
grant select,drop on db1.* to 'lin2'@'localhost' identified by '123';


#级别3:对表db1.t1,下的所有字段
grant select on db1.t1 to 'lin3'@'localhost' identified by '123';

#级别4:对表db1.t1,下的id,name字段
grant select (id,name) on db1.t1 to 'lin4'@'localhost' identified by '123';
grant select (id,name),update (name) on db1.t1 to 'lin5'@'localhost' identified by '123';

#修改完权限后,要记得刷新权限
flush privileges;

3-约束
-偏移量------步长------单列唯一-----多列唯一
1 not null 与default

create table student2(
id int primary key auto_increment,
name char(5),
sex enum('male','female') not null default 'female'
);

insert into student2(name) values('alex');


create table student3(
id int primary key auto_increment,
name char(5),
age int not null default 30
);

insert into student3(name) values('alex');


2 unique
#单列唯一
create table teacher(
id int not null unique,
name char(10)
);
insert into teacher values(1,'egon');
insert into teacher values(1,'alex');

#多列唯一
#255.255.255.255
create table services(
id int primary key auto_increment,
name char(10),
host char(15),
port int,
constraint host_port unique(host,port)
);

insert into services values('ftp','192.168.20.17',8080);
insert into services values('httpd','192.168.20.17',8081);




#auto_increment_offset:偏移量
create table dep(
id int primary key auto_increment,
name char(10)
);
insert into dep(name) values('IT'),('HR'),('SALE'),('Boss');

create table dep1(
id int primary key auto_increment,
name char(10)
)auto_increment=10;
insert into dep1(name) values('IT'),('HR'),('SALE'),('Boss');


#auto_increment_increment:步长
create table dep2(
id int primary key auto_increment,
name char(10)
);
set session auto_increment_increment=2; #会话级,只对当前会话有效
set global auto_increment_increment=2; #全局,对所有的会话都有效
insert into dep1(name) values('IT'),('HR'),('SALE'),('Boss');


#auto_increment_offset:偏移量+auto_increment_increment:步长
注意:如果auto_increment_offset的值大于auto_increment_increment的值,则auto_increment_offset的值会被忽略
set session auto_increment_offset=2;
set session auto_increment_increment=3;
show variables like '%auto_in%';

create table dep3(
id int primary key auto_increment,
name char(10)
);
insert into dep3(name) values('IT'),('HR'),('SALE'),('Boss');


4-键表与表之间的关系
1 多对一:左边表的多条记录对应右面表的唯一一条记录
create table dep(
id int primary key auto_increment, #被关联的字段必须保证是唯一的
name varchar(20),
comment varchar(50)
);


create table emp(
id int primary key auto_increment,
name varchar(20),
dep_id int, #关联的字段,一定要保证是可以重复的
constraint fk_depid_id foreign key(dep_id) references dep(id)
on update cascade
on delete cascade
);

建立多对一的关系需要注意
1 先建立被关联的表,被关联的字段必须保证是唯一的
2 再创建关联的表,关联的字段,一定要保证是可以重复的
ps:关联的字段一定是来自于表关联的表对应字段的值


2 一对一的关系:
1. 先建立被关联的表,被关联的表示唯一的
create table user(
uid int primary key auto_increment,
name varchar(15)
);
insert into user(name) values
('egon1'),
('egon2'),
('egon3'),
('egon4'),
('egon5'),
('egon6');



create table admin(
id int primary key auto_increment,
user_id int unique,
password varchar(20),
foreign key(user_id) references user(uid)
on update cascade
on delete cascade
);


insert into admin(user_id,password) values
(3,'alex3714'),
(5,'alex371asdf4')
;

5-多表查询
 
1 简单查询
select * from employee;
select name,salary from employee;

2 where条件
select name,salary from employee where salary > 10000;
select name,salary from employee where salary > 10000 and salary < 20000;
select name,salary from employee where salary between 10000 and 20000;
select name,salary from employee where salary not between 10000 and 20000;

select name,salary from employee where salary = 10000 or salary = 20000 or salary = 30000;
select name,salary from employee where salary in (10000,20000,30000);


select * from employee where salary = 10000 or age = 18 or sex='male';

select * from employee where post_comment is Null;
select * from employee where post_comment = Null;
select * from employee where post_comment is not Null;

select * from employee where name like '%n%';

select * from employee where name like 'e__n';
 
 

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转载自www.cnblogs.com/806939095xbb/p/7593868.html