多线程问题之按序打印

一、题目描述

我们提供了一个类:
public class Foo {
public void first() { print(“first”); }
public void second() { print(“second”); }
public void third() { print(“third”); }
}
三个不同的线程 A、B、C 将会共用一个 Foo 实例。
一个将会调用 first() 方法
一个将会调用 second() 方法
还有一个将会调用 third() 方法
请设计修改程序,以确保 second() 方法在 first() 方法之后被执行,third() 方法在 second() 方法之后被执行。
示例 1:
输入: [1,2,3]
输出: “firstsecondthird”
解释:
有三个线程会被异步启动。
输入 [1,2,3] 表示线程 A 将会调用 first() 方法,线程 B 将会调用 second() 方法,线程 C 将会调用 third() 方法。
正确的输出是 “firstsecondthird”。
示例 2:
输入: [1,3,2]
输出: “firstsecondthird”
解释:
输入 [1,3,2] 表示线程 A 将会调用 first() 方法,线程 B 将会调用 third() 方法,线程 C 将会调用 second() 方法。
正确的输出是 “firstsecondthird”。

二、题解
方法一:使用ReentrantLock

class Foo {
    
    
    private int number = 1;
    private Lock lock = new ReentrantLock();
    private Condition condition1 = lock.newCondition();
    private Condition condition2 = lock.newCondition();
    private Condition condition3 = lock.newCondition();
    public Foo() {
    
    
        number = 1;
    }

    public void first(Runnable printFirst) throws InterruptedException {
    
    
        
        lock.lock();
        try{
    
    
            if(number!=1){
    
    
                condition1.await();
            }
            // printFirst() outputs "first". Do not change or remove this line.
            printFirst.run();
            number = 2;
            condition2.signal();
        }finally{
    
    
            lock.unlock();
        }
    }

    public void second(Runnable printSecond) throws InterruptedException {
    
    
       lock.lock();
        try{
    
    
            if(number != 2){
    
    
                condition2.await();
            }
            // printSecond() outputs "second". Do not change or remove this line.
            printSecond.run();
            number = 3;
            condition3.signal();
        }finally{
    
    
            lock.unlock();
        }
    }

    public void third(Runnable printThird) throws InterruptedException {
    
    
     lock.lock();
        try{
    
    
            if(number != 3)
                condition3.await();
            // printThird.run() outputs "third". Do not change or remove this line.
			printThird.run();
            number = 1;
            condition1.signal();
        }finally{
    
    
            lock.unlock();
        }
    }
}

-方法二:使用Atomic

class Foo {
    
    
    private AtomicInteger firstJobDone = new AtomicInteger(0);
    private AtomicInteger secondJobDone = new AtomicInteger(0);
    public Foo() {
    
    
        
    }

    public void first(Runnable printFirst) throws InterruptedException {
    
    
        
        // printFirst() outputs "first". Do not change or remove this line.
        printFirst.run();
        firstJobDone.incrementAndGet();
    }

    public void second(Runnable printSecond) throws InterruptedException {
    
    
        while(firstJobDone.get()!=1){
    
    

        }
        // printSecond() outputs "second". Do not change or remove this line.
        printSecond.run();
        secondJobDone.incrementAndGet();
    }

    public void third(Runnable printThird) throws InterruptedException {
    
    
        while(secondJobDone.get()!=1){
    
     
        }
        // printThird.run() outputs "third". Do not change or remove this line.
		printThird.run();
    }
}

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转载自blog.csdn.net/qq_38748148/article/details/113786400