简单三子棋的实现

总体思路：借助二维数组模拟棋盘，首先创建一个棋盘，然后对棋盘进行初始化，初始化内容为空格。然后玩家进行下棋的操作，随后判断一次输赢，然后电脑进行下棋操作，随后判断输赢。

#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define ROW 3
#define COL 3


void menu()//显示菜单
{
	printf("*********************\n");
	printf("*****  1. Play	*****\n");
	printf("*****  0. Exit	*****\n");
	printf("*********************\n");
}


void initBoard(char board[ROW][COL], int row, int col)//初始化棋盘为 空格
{
	int i = 0;
	int j = 0;
	for (i = 0;i < row;i++)
	{
		for (j = 0;j < col;j++)
		{
			board[i][j] = ' ';
		}
	}
}

//棋盘样式
//	  |   |   
// ---|---|---
//    |   |  
// ---|---|---
//    |   |

void DisplayBoard(char board[ROW][COL], int row, int col)//显示棋盘
{
	int i = 0;
	int j = 0;
	for (i = 0;i < row;i++)
	{
		for (j = 0;j < col;j++)//这样可以自由控制棋盘的行列大小
		{
			printf(" %c ", board[i][j]);
			if (j != col - 1)
				printf("|");
		}
		printf("\n");
		for (j = 0;j < col;j++)
		{
			if (i != row - 1)
			{
				printf("---");
				if (j != col - 1)
					printf("|");
			}
		}
		printf("\n");
	}
}


void Playermove(char board[ROW][COL], int row, int col)//玩家操作
{
	while (1)
	{
		int x = 0;
		int y = 0;
		printf("请输入棋盘对应坐标来进行下棋\n");
		scanf("%d%d", &x, &y);
		if (board[x - 1][y - 1] == ' ')
		{
			board[x - 1][y - 1] = '#';
			break;
		}
		else
		{
			printf("你输入的位置不正确！\n");
		}
	}
}

void Computermove(char board[ROW][COL], int row, int col)//电脑操作
{
	while (1)
	{
		int x = rand() % row;//生成坐标
		int y = rand() % col;
		if (board[x][y] == ' ')
		{
			board[x][y] = '*';
			break;
		}
	}
}

	
char Is_Win(char board[ROW][COL], int row, int col)
{
	//玩家赢或电脑赢，然后返回赢的那个字符
	int i = 0;
	int j = 0;
	for (i = 0;i < row;i++)
	{
		if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1]!=' ')
			return board[i][1];
	}
	for (j = 0;j < col;j++)
	{
		if (board[0][j] == board[1][j] && board[1][j] == board[2][j] && board[1][j] && board[1][j]!=' ')
			return board[1][j];
	}
	if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
		return board[1][1];
	if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
		return board[1][1];
	for (i = 0;i < row;i++)
	{
		for (j = 0;j < col;j++)
		{
			if(board[i][j] == ' ')
				return 1;//只要棋盘没满就返回1
		}
	}
	return 0;//以上条件如果都不满足，那么棋盘就是满的，也就是平局
}


void game()//游戏
{
	char board[ROW][COL] = { 0 };
	initBoard(board, ROW, COL);//初始化棋盘
	DisplayBoard(board, ROW, COL);//展示棋盘
	char ret = 0;
	while (1)
	{
		Playermove(board, ROW, COL);//玩家操作
		ret = Is_Win(board, ROW, COL);
		if (ret != 1)
			break;
		DisplayBoard(board, ROW, COL);
		Computermove(board, ROW, COL);//电脑操作
		DisplayBoard(board, ROW, COL);
		ret = Is_Win(board, ROW, COL);
		if (ret != 1)
			break;
	}
	if (ret == '#')
	{
		printf("恭喜你赢了\n");
	}
	if (ret == '*')
	{
		printf("你输了！\n");
	}
	if (ret == 0)
	{
		printf("平局！\n");
	}
}

int main()
{
	int input = 0;
	srand((size_t)time(NULL));
	do
	{
		menu();
		printf("请输入数字去选择\n");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;
		case 0:
			printf("退出成功!\n");
			break;
		default:
			printf("选择错误！\n");
			break;
		}
	} while (input);
	return 0;
}