import urllib.request
import urllib.error
url = "http://www.google.com" # 正确url:http://www.google.cn
try:
resp = urllib.request.urlopen(url)
except urllib.error.URLError as e:
print(e.reason)
urllib.error.URLError异常处理
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转载自blog.csdn.net/qq_46620129/article/details/114329791
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