package banker;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
/**
* @author lele
* @title 银行家算法
* @date 2020-10-31
*/
public class BankerAlgorithm {
private Integer processNumber;//进程数量
private Integer resourceTypeNumber;//资源类型数量
private List<Process> processes;//所有进程集合
private List<Resource> resources;//所有资源集合
/**
* @param processNumber 进程数量
* @param resourceTypeNumber 资源类型数量
* @param initResourceAvailable 资源初始值
* @param initProcessMax 进程对各类资源的最大需求量
* @param initProcessAllocation 当前时刻进程对各类资源的占有量
*/
public BankerAlgorithm(Integer processNumber, Integer resourceTypeNumber, List<Integer> initResourceAvailable,
List<List<Integer>> initProcessMax, List<List<Integer>> initProcessAllocation) {
this.processNumber = processNumber;
this.resourceTypeNumber = resourceTypeNumber;
Process.resourceTypeNumber = this.resourceTypeNumber;
resources = new ArrayList<>(resourceTypeNumber);//创建资源集合
processes = new ArrayList<>(processNumber);//创建进程集合
//初始化各类资源
for (int i = 0; i < resourceTypeNumber; i++) {
resources.add(new Resource(initResourceAvailable.get(i)));
}
//初始化各个进程信息
for (int i = 0; i < processNumber; i++) {
processes.add(new Process(initProcessMax.get(i), initProcessAllocation.get(i)));
}
}
/**
* 第i号进程对各类资源提出的资源请求
*
* @param i 进程编号
* @param requestParam 对各类资源请求的数目
* @return 返回是否可以请求成功
*/
public boolean request(Integer i, List<Integer> requestParam) {
Process process = processes.get(i);
boolean flag = true;
//判断当前资源请求数量是否大于该进程宣布的资源请求数量
for (int j = 0; j < resourceTypeNumber; j++) {
if (requestParam.get(j) > process.need.get(j)) {
flag = false;
break;
}
}
if (flag) {
//判断各类资源是否能够满足请求的资源数目
for (int j = 0; j < resourceTypeNumber; j++) {
if (requestParam.get(j) > resources.get(j).available) {
flag = false;
break;
}
}
if (flag) {
//试图将资源分配给该进程,修改相关数据值
for (int j = 0; j < resourceTypeNumber; j++) {
resources.get(j).available -= requestParam.get(j);
process.allocation.set(j, process.allocation.get(j) + requestParam.get(j));
process.need.set(j, process.need.get(j) - requestParam.get(j));
}
//安全性算法检验
if (isSafety()) {
//若安全,则正式分配
System.out.println("安全,可正式分配");
return true;
} else {
//若不安全,则回滚数据
for (int j = 0; j < resourceTypeNumber; j++) {
resources.get(j).available += requestParam.get(j);
process.allocation.set(j, process.allocation.get(j) - requestParam.get(j));
process.need.set(j, process.need.get(j) + requestParam.get(j));
}
System.out.println("进入不安全状态,不分配资源!");
return false;
}
} else {
System.out.println("尚无足够资源,需等待...");
return flag;
}
} else {
System.out.println("错误:需要的资源已经超过了宣布的最大值!");
return flag;
}
}
/**
* 安全性算法检查
*
* @return 返回安全性结果
*/
public boolean isSafety() {
//初始化当前工作向量work
ArrayList<Integer> work = new ArrayList<>(resourceTypeNumber);
for (Resource resource : resources) {
work.add(resource.available);
}
//初始化finish为false
ArrayList<Boolean> finish = new ArrayList<>(processNumber);
for (int i = 0; i < processNumber; i++) {
finish.add(false);
}
//用于对所有循环的遍历,若在一次遍历中所有进程都不满足要求,则遍历结束
boolean repeat;
//遍历每个进程
do {
repeat = false;
for (int i = 0; i < processes.size(); i++) {
Process process = processes.get(i);
if (finish.get(i) == false) {
//判断当前进程是否满足:根据当前各类资源的数量,是否可以完成自己的需求,即need
boolean flag = true;
for (int j = 0; j < resourceTypeNumber; j++) {
if (process.need.get(j) > work.get(j)) {
flag = false;
break;
}
}
//若满足需求,则该进程则归还给系统自己所占有的全部资源
if (flag) {
for (int j = 0; j < resourceTypeNumber; j++) {
work.set(j, process.allocation.get(j) + work.get(j));
finish.set(i, true);
}
System.out.println("进程编号:" + i);
repeat = true;
}
}
}
} while (repeat);
boolean flag = true;
for (Boolean f : finish) {
if (f == false) {
flag = false;
break;
}
}
return flag;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("process number");
Integer processNumber = in.nextInt();
System.out.println("resourceTypeNumber number");
Integer resourceTypeNumber = in.nextInt();
//输入各类资源数量
List<Integer> initResourceAvailable = new ArrayList<>();
for (int i = 0; i < resourceTypeNumber; i++) {
initResourceAvailable.add(in.nextInt());
}
List<List<Integer>> initProcessMax = new ArrayList<>();
List<Integer> max;
//输入各个进程对各类资源的最大需求量
for (int i = 0; i < processNumber; i++) {
max = new ArrayList<>();
for (int j = 0; j < resourceTypeNumber; j++) {
max.add(in.nextInt());
}
initProcessMax.add(max);
}
List<List<Integer>> initProcessAllocation = new ArrayList<>();
//输入各个进程对各类资源当前的占有量
List<Integer> allocation;
for (int i = 0; i < processNumber; i++) {
allocation = new ArrayList<>();
for (int j = 0; j < resourceTypeNumber; j++) {
allocation.add(in.nextInt());
}
initProcessAllocation.add(allocation);
}
//初始化
BankerAlgorithm bankerAlgorithm = new BankerAlgorithm(processNumber, resourceTypeNumber, initResourceAvailable, initProcessMax, initProcessAllocation);
//模拟书上例题
System.out.println("T0时刻:" + bankerAlgorithm.isSafety());
ArrayList<Integer> requestParam = new ArrayList<>();
requestParam.add(1);
requestParam.add(0);
requestParam.add(2);
System.out.println("P1请求资源:" + bankerAlgorithm.request(1, requestParam));
requestParam.clear();
requestParam.add(3);
requestParam.add(3);
requestParam.add(0);
System.out.println("P4请求资源:" + bankerAlgorithm.request(4, requestParam));
requestParam.clear();
requestParam.add(0);
requestParam.add(2);
requestParam.add(0);
System.out.println("P0请求资源:" + bankerAlgorithm.request(0, requestParam));
//模拟练习题最后一道
/*
System.out.println(bankerAlgorithm.isSafety());
ArrayList<Integer> requestParam = new ArrayList<>();
requestParam.add(1);
requestParam.add(2);
requestParam.add(2);
requestParam.add(2);
System.out.println(bankerAlgorithm.request(2,requestParam));
*/
}
}
//进程类
class Process {
//每个进程所持有的资源类别数量相等
public static Integer resourceTypeNumber;//资源类别数量
public List<Integer> max;//对各类资源的最大需求数目
public List<Integer> allocation;//进程已经分配到的各类资源的数目
public List<Integer> need = new ArrayList<>(resourceTypeNumber);//进程需要的各类资源的数目
public Process(List<Integer> max, List<Integer> allocation) {
this.max = max;
this.allocation = allocation;
for (int i = 0; i < resourceTypeNumber; i++) {
need.add(max.get(i) - allocation.get(i));
}
}
}
//资源类
class Resource {
public Integer available;//资源的空闲数目
//初始化资源空闲数
public Resource(Integer available) {
this.available = available;
}
}
/*
模拟书上例题数据
process number
5
resourceTypeNumber number
4
1
6
2
2
0
0
4
4
2
7
5
0
3
6
10
10
0
9
8
4
0
6
6
10
0
0
3
2
1
0
0
0
1
3
5
4
0
3
3
2
0
0
1
4
*/
/*
模拟练习题最后一道
process number
5
resourceTypeNumber number
3
3
3
2
7
5
3
3
2
2
9
0
2
2
2
2
4
3
3
0
1
0
2
0
0
3
0
2
2
1
1
0
0
2
*/
银行家算法(Java版)附测试数据
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转载自blog.csdn.net/qq_44486437/article/details/109405962
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