浙大Python 第3章-9 字符串转换成十进制整数 (15 分)

原题题目

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代码实现（看了下人家的才知道自己写的多麻烦）

string = input()
strl = len(string);retstr = '';firstflag = 0;symflag = 0;flag = 0
for i in range(strl):
    if(string[i] == '-'):  symflag = 1
    elif('0'<=string[i]<='9' or 'a'<=string[i]<='f' or 'A'<=string[i]<='F'):
        retstr += string[i]
        if (firstflag == 0 and symflag == 1):    flag = 1
        firstflag = 1

if(len(retstr) >= 1):
    if(flag == 1):
        print("%d" % (int(retstr, 16) * -1))
    else:
        print("%d" % int(retstr, 16))
else:
    print('0')

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提交结果