题意： 给出数列长度n与正整数m，试问该数列是否满足
正好等于m，且除法过程中不是整除(即 5/2 == 2.5)。
思路： 仔细观察不难发现其实该题问的就是是否数列和正好等于m。
代码实现：
#include<bits/stdc++.h>
#define endl '\n'
#define null NULL
#define ll long long
#define int long long
#define pii pair<int, int>
#define lowbit(x) (x &(-x))
#define ls(x) x<<1
#define rs(x) (x<<1+1)
#define me(ar) memset(ar, 0, sizeof ar)
#define mem(ar,num) memset(ar, num, sizeof ar)
#define rp(i, n) for(int i = 0, i < n; i ++)
#define rep(i, a, n) for(int i = a; i <= n; i ++)
#define pre(i, n, a) for(int i = n; i >= a; i --)
#define IOS ios::sync_with_stdio(0); cin.tie(0);cout.tie(0);
const int way[4][2] = {
{
1, 0}, {
-1, 0}, {
0, 1}, {
0, -1}};
using namespace std;
const int inf = 0x7fffffff;
const double PI = acos(-1.0);
const double eps = 1e-6;
const ll mod = 1e9 + 7;
const int N = 2e5 + 5;
int t, n, m;
signed main()
{
IOS;
cin >> t;
while(t --){
cin >> n >> m;
int sum = 0;
while(n --){
int x; cin >> x;
sum += x;
}
cout << (sum==m? "YES":"NO") << endl;;
}
return 0;
}