P2044 [NOI2012] 随机数生成器
解题思路:
[ x [ i − 1 ] c ] ∗ [ a 0 1 1 ] = [ x [ i ] c ] \begin{bmatrix}x[i-1]&c\end{bmatrix}*\begin{bmatrix}a& 0\\1&1\end{bmatrix}= \begin{bmatrix}x[i]&c\end{bmatrix} [x[i−1]c]∗[a101]=[x[i]c]
注意:相乘可能爆long long,所以需要龟速乘。
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double lf;
typedef unsigned long long ull;
typedef pair<int,int>P;
const int inf = 0x7f7f7f7f;
const ll INF = 1e16;
const int N = 1e5+10;
//const ll mod = 1e9+7;
const double PI = acos(-1.0);
const double eps = 1e-4;
inline int read(){int x=0,f=1;char ch=getchar();while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}return x*f;}
inline string readstring(){string str;char s=getchar();while(s==' '||s=='\n'||s=='\r'){s=getchar();}while(s!=' '&&s!='\n'&&s!='\r'){str+=s;s=getchar();}return str;}
int random(int n){return (int)(rand()*rand())%n;}
void writestring(string s){int n = s.size();for(int i = 0;i < n;i++){printf("%c",s[i]);}}
typedef struct node{
ll mx[3][3];
}mx;
ll Wuguidechengfa(ll x,ll y,ll mod){
ll ans=0;
while(y){
if(y&1) (ans+=x)%=mod;
(x+=x)%=mod;
y>>=1;
}
return ans;
}
mx multiply(mx a,mx b,ll mod){
mx c;
for(int i = 1;i <= 2;i++){
for(int j = 1;j <= 2;j++){
c.mx[i][j] = 0;
for(int k = 1;k <= 2;k++){
c.mx[i][j] = (c.mx[i][j]+Wuguidechengfa(a.mx[i][k],b.mx[k][j],mod))%mod;
}
}
}
return c;
}
mx fast_power(mx a,ll p,ll mod){
mx ans;
ans.mx[1][1]=ans.mx[2][2]=1;
ans.mx[1][2]=ans.mx[2][1]=0;
while(p){
if(p&1) ans = multiply(ans,a,mod);
p >>= 1;
a = multiply(a,a,mod);
}
return ans;
}
int main(){
// srand((unsigned)time(NULL));
mx base;
base.mx[1][2]=0;base.mx[2][1]=1;base.mx[2][2]=1;
ull m,a,c,x0,n,g;
cin >> m >> a >> c >> x0 >> n >> g;
base.mx[1][1] = a%m;
c %= m;
x0 %= m;//x0,c,a
base = fast_power(base,n,m);
ll ans = ((Wuguidechengfa(x0,base.mx[1][1],m))+(Wuguidechengfa(c,base.mx[2][1],m)))%m;
ans %= g;
cout<<ans<<endl;
return 0;
}