select a.* , datediff(a.第二次消费时间, a.第一次消费时间) 间隔 from
(select m.card_code , m.realname , m.mobile ,
substring_index(group_concat(o.begin_date order by o.begin_date), ',' , 1) 第一次消费时间 ,
substring_index(group_concat(o.begin_date order by o.begin_date desc), ',' , 1) 第二次消费时间
from `order` o
left join member m on o.member_id = m.id
left join shop s on o.counter_code = s.`code`
where o.member_id > 0
and o.begin_date between '2019-11-06 00:00:00' and '2019-11-17 23:59:59'
and s.city = '廊坊'
group by o.member_id
having count(o.member_id) = 2)a