【LeetCode】【数组】题号：*453，数组元素相等的最小操作次数

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0. 前言

无

1. 正文

1.1 题目

1.2 题解

python:

class Solution:
    def minMoves(self, nums: List[int]) -> int:

        # 每个元-1，减到最小位置
        min = nums[0]
        for i in nums:
            if min> i:
                min = i
        
        count = 0
        for i in nums:
            count += i-min
        return count

1.3 结果