1.reduce()方法实现数组对象去重（reduce方法没搞明白过）
// 测试
getTest1() {
const array1 = [
{
userId: 12277, insuranceProbability: '0.55', nonInsuranceProbability: '0.33' },
{
userId: 10253, insuranceProbability: '0.65', nonInsuranceProbability: '0.38' },
{
userId: 12277, insuranceProbability: '0.55', nonInsuranceProbability: '0.33' },
{
userId: 10253, insuranceProbability: '0.65', nonInsuranceProbability: '0.38' },
{
userId: 12277, insuranceProbability: '0.55', nonInsuranceProbability: '0.33' }
]
const obj = {
}
const open = array1.reduce((total, item) => {
console.log(total, '111')
console.log(item, '222')
obj[item.userId] ? '' : obj[item.userId] = true && total.push(item)
return total
}, [])
console.log(open, 'open----')
}
}
打印结果
（reduce使用详解：默认穿了个空数组，那ruduce第一个参数total就默认是空数组，第二个参数item拿的是array数组的第一项，若是不传默认值，则total拿的是array数组的第一项，item拿的是数组的第二项，reduce函数内需要给return值，因为total下一下拿的就是return的值，若没有则total打印的是undefined,第二个参数item还是会依次去取array后面几项的值，一般数组求和用reduce是真香）
2.数组对象相同id的进行数据合并 （代码拿的这个小可爱的）
（userId是一样的，但是其它的值不一样的话，我想拿到最终的修改值）
getTest2() {
const array = [
{
userId: 12277, insuranceProbability: '0.51', nonInsuranceProbability: '0.33' },
{
userId: 10253, insuranceProbability: '0.65', nonInsuranceProbability: '0.38' },
{
userId: 12277, insuranceProbability: '0.58', nonInsuranceProbability: '0.39' },
{
userId: 10253, insuranceProbability: '0.82', nonInsuranceProbability: '0.18' },
{
userId: 12277, insuranceProbability: '0.58', nonInsuranceProbability: '0.36' }
]
const idList = [] // 存放userId
const newArray = [] // 新数组
for (let i = 0; i < array.length; i++) {
// 循环array数组
if (idList.indexOf(array[i].userId) === -1) {
// 将第一次出现的userId存到idList
idList.push(array[i].userId)
// 第一次出现的userId没有重复，所以该项（array[i]）存进newArray
newArray.push(array[i])
} else {
// 出现重复的userId
// 将此项覆盖掉newArray内相同userId的那一项
newArray.splice(idList.indexOf(array[i].userId), 1, array[i])
}
console.log(idList, newArray, {
...newArray })
}
打印结果：
最后说一句，ES6真香啊