list和dict的应用

list和dict的应用

给定一个list和dict,返回list中元素不存在dict的key、存在dict但是value为空、存在dict但是value为0的结果。

直接上代码

def isnotexsit(dict1, list1):
    '''
    给一个字典,列表,返回字典对应key不存在列表的结果集
    :param dict: {},[]
    :return: []
    '''
    # 获取dict对应可以
    list2 = []
    list3 = []
    dict_key = dict1.keys()
    for i in list1:
        if i in dict_key:
            list3.append(i)
        else:
            list2.append(i)
    return {'not': list2, 'yes': list3}

def isnull(dict1, list1):
    '''
    获取dict中value为null的结果
    :param dict:
    :return: []
    '''
    l = isnotexsit(dict1, list1)
    k = l.get('yes')
    list1 = []
    list2=[]
    for i in k:
        a = dict1.get(i)
        if str(a).strip()=='':
    	    list1.append(i)
        elif int(dict1[i])==0:
            list2.append(i)
    return list1,list2

def result(dict1, list1):
    '''
    数据组装
    :param dict1:
    :param list1:
    :return: 不存在list,为空list,为0 list
    '''
    a = isnotexsit(dict1, list1)
    nexsit = a.get('not')
    null_exsit,exit_0 = isnull(dict1, list1)
    return nexsit,null_exsit,exit_0

调式

if __name__ == '__main__':
    dict1={"faceLivenessResult": {
        "thresholdE4": '',
        "thresholdE5":' ',
        "thresholdE3": 65.3,
        "intermediaryDeviceNum": 0
    },
    "userRelationInfo": {
        "pyramidSaleCountD1": '',
        "pyramidSaleCountD2": 0,
        "asAgent2Num": 0,
        "intermediaryDeviceNum": 0
    }}
    dict2={"faceLivenessResult": [
        "thresholdE4",
        "thresholdE5",
        "thresholdE3",
        "intermediaryDeviceNum",
        "a"
    ],
    "userRelationInfo": [
        "pyramidSaleCountD1",
        "pyramidSaleCountD2",
        "asAgent2Num",
        "intermediaryDeviceNum"
    ]}
    for key in dict2.keys():
        nexsit,null_exsit,exit_0=result(dict1[key],dict2[key])
        print({key:{"不存在的key":nexsit, "结果为空的":null_exsit, "结果为0的": exit_0}})```
    

## 运行结果

在这里插入代码片


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转载自blog.csdn.net/kairui_guxiaobai/article/details/104696589