php获取当天的日期-年月日与星期几

代码如下:

<?php
	function getNow(){
        $data = [];
        $format='Y.m.d';
        for ($i=0; $i<1; $i++){
            $strtotime = strtotime( '+' .$i.' days');
            $data[$i]['date'] = date($format ,$strtotime);
            $data[$i]['week'] = "星期" . mb_substr( "日一二三四五六",date("w" ,$strtotime),1,"utf-8" );
        }

        return $data;
    }
	 var_dump(getNow());
	
?>

效果如下:

参考自:https://www.cnblogs.com/bluealine/p/10243144.html

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转载自blog.csdn.net/z3287852/article/details/113662760
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