没什么难的
注意如果l > r, swap(l, r)
// Decline is inevitable,
// Romance will last forever.
//#include <bits/stdc++.h>
#include <iostream>
#include <cmath>
#include <cstring>
#include <string>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <deque>
#include <vector>
using namespace std;
#define mst(a, x) memset(a, x, sizeof(a))
#define INF 0x3f3f3f3f
//#define ll long long
#define int long long
const int maxn = 1e5 + 10;
//const int P = 1e9 + 7;
int n, m, q;
int P;
int a[maxn];
struct segement_tree {
int l, r;
int sum;
#define sum(x) tree[x].sum
#define l(x) tree[x].l
#define r(x) tree[x].r
}tree[maxn << 2];
void push(int p) {
sum(p) = sum(p<<1) + sum(p << 1 | 1);
}
void build(int p, int l, int r) {
l(p) = l; r(p) = r;
if(l == r) {
sum(p) = a[l];
return;
}
int mid = (l + r) >> 1;
build(p<<1, l, mid);
build(p<<1|1, mid + 1, r);
push(p);
}
void change(int p, int l, int r) {
if(r(p) == l(p)) {
sum(p) = sqrt(sum(p));
return;
}
if(r(p)-l(p)+1 >= sum(p)) return;
int mid = (l(p) + r(p)) >> 1;
if(l <= mid) change(p<<1, l, r);
if(r > mid) change(p<<1|1, l, r);
push(p);
}
int query(int p, int l, int r) {
if(l <= l(p) && r >= r(p)) return sum(p);
int ans = 0;
int mid = (l(p) + r(p)) >> 1;
if(l <= mid) ans += query(p<<1, l, r);
if(r > mid) ans += query(p<<1|1, l, r);
return ans;
}
void solve() {
int t = 0;
while(cin >> n) {
for(int i = 1; i <= n; i++)
cin >> a[i];
for(int i = 1; i <= 4*n; i++)
tree[i].sum = 0;
build(1, 1, n);
t++;
cout << "Case #" << t << ":\n";
cin >> m;
while(m--) {
int l, r, k;
cin >> k >> l >> r;
if(l > r) swap(l, r);
if(!k) {
change(1, l, r);
}
else {
cout << query(1, l, r) << '\n';
}
}
cout << '\n';
}
}
signed main() {
ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
// int T;
// cin >> T;
// while(T--)
solve();
return 0;
}