漫话Redis源码之四

digits10的实现简直亮晕了双眼，居然这么巧妙，主要是基于效率的考虑：

/* Modify the buffer replacing all occurrences of chars from the 'from'
 * set with the corresponding char in the 'to' set. Always returns s.
 */
char *memmapchars(char *s, size_t len, const char *from, const char *to, size_t setlen) {
    for (size_t j = 0; j < len; j++) {
        for (size_t i = 0; i < setlen; i++) {
            if (s[j] == from[i]) {
                s[j] = to[i];
                break;
            }
        }
    }
    return s;
}

/* Return the number of digits of 'v' when converted to string in radix 10.
 * See ll2string() for more information. */
uint32_t digits10(uint64_t v) {
    if (v < 10) return 1;
    if (v < 100) return 2;
    if (v < 1000) return 3;
    if (v < 1000000000000UL) {
        if (v < 100000000UL) {
            if (v < 1000000) {
                if (v < 10000) return 4;
                return 5 + (v >= 100000);
            }
            return 7 + (v >= 10000000UL);
        }
        if (v < 10000000000UL) {
            return 9 + (v >= 1000000000UL);
        }
        return 11 + (v >= 100000000000UL);
    }
    return 12 + digits10(v / 1000000000000UL);
}

/* Like digits10() but for signed values. */
uint32_t sdigits10(int64_t v) {
    if (v < 0) {
        /* Abs value of LLONG_MIN requires special handling. */
        uint64_t uv = (v != LLONG_MIN) ?
                      (uint64_t)-v : ((uint64_t) LLONG_MAX)+1;
        return digits10(uv)+1; /* +1 for the minus. */
    } else {
        return digits10(v);
    }
}