习题8-18(uva-1619)

#include <iostream>
#include <istream>
#include <sstream>
#include <vector>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <cstring>
#include <unordered_map>
#include <unordered_set>
#include <algorithm>
#include <numeric>
#include <chrono>
#include <ctime>
#include <cmath>
#include <cctype>
#include <string>
#include <cstdio>
#include <iomanip>


#include <thread>
#include <mutex>
#include <condition_variable>
#include <functional>
#include <iterator>
using namespace std;
const int maxn = 1e5 + 7;
int input[maxn], l[maxn], r[maxn], n;
//和可能超过int
long long int sum[maxn] = {
    
     0 };

int main()
{
    
    
	int kCase = 0;
	while (cin >> n && n) {
    
    
		for (int i = 1; i <= n; i++) {
    
    
			cin >> input[i];
			l[i] = r[i] = i; 
			sum[i] = sum[i - 1] + input[i];
		}
		
		input[0] = input[n + 1] = -1;
		for (int i = 1; i <= n; i++) {
    
    
			while (input[i] <= input[l[i] - 1])l[i] = l[l[i] - 1];
		}
		for (int i = n; i >= 1; i--) {
    
    
			while (input[i] <= input[r[i] + 1])r[i] = r[r[i] + 1];
		}
		long long int  ans = 0, ansL = 1, ansR = 1;
		for (int i = 1; i <= n; i++) {
    
    
			long long int  s = (long long int)input[i] * (sum[r[i]] - sum[l[i] - 1]);
			if (s  > ans || (s == ans &&  (r[i] - l[i]) < (ansR - ansL))) {
    
    
				ans = s;
				ansL = l[i];
				ansR = r[i];
			}
		}
		if (kCase++) cout << endl;
		cout << ans << endl << ansL << " " << ansR << endl;
	}
	return 0;
}