1.用一条sql语句,查询出每门课都大于80分的学生姓名。
name kecheng fenshu
张三 语文 81
张三 数学 75
李四 语文 76
李四 数学 90
王五 语文 81
王五 数学 100
王五 英语 90
select distinct t1.name from stu_grade t1 where t1.name not in ( select distinct t2.name from stu_grade t2 where t2.fenshu < 80 );
2.学生表如下:
id sn name course_id course_name grade
1 2005001 张三 0001 数学 69
2 2005002 李四 0001 数学 89
3 2005001 张三 0001 数学 69
删除除了id不同,其他都相同的学生冗余信息。
#oracle delete from student where id not in ( select min(id) from student as t group by sn,name,course_id,course_name,grade );
(1)在where的左右都不能使用组函数;
(2)一般,可以使用exists代替in,但是在in的条件中使用了组函数查询到值,就不能用exists代替。
#mysql delete student as a from student as a, ( select *, min(id) from student group by sn,name,course_id,course_name,grade having count(1) >1 ) as b where a.sn=b.sn and a.name=b.name and a.course_id=b.course_id and a.course_name=b.course_name and a.grade=b.grade and a.id>b.id;
#mysql delete from student where id not in ( select temp.value from (select min(id) value from student as t group by sn,name,course_id,course_name,grade) as temp );
3. 插入相同记录。
insert into student(sn,name,course_id,course_name,grade) select sn,name,course_id,course_name,grade from student where id=7;
4.现有球队表team,只有一个字段name,共4条记录,A,B,C,D为四只球队的名称。4只球队进行比赛,用一条sql语句写出所有可能比赛的组合。
select t2.name, t1.name from team t1, team t2 where t1.name != t2.name;
5. 原表为:
course_id course_name score
1 java 70
2 oracle 90
3 xml 40
4 jsp 30
5 servlet 80
为了便于阅读,查询此表后的结果显示如下:(及格分数为60):
course_id course_name score mark
1 java 70 pass
2 oracle 90 pass
3 xml 40 fail
4 jsp 30 fail
5 servlet 80 pass
select *,IF(score<60,"fail","pass") as mark from course;
6.表a:
year month amount
1991 1 1.1
1991 2 1.2
1991 3 1.3
1991 4 1.4
1992 1 2.1
1992 2 2.2
1992 3 2.3
1992 4 2.4
用sql语句,查询成下面结果:
year m1 m2 m3 m4
1991 1.1 1.2 1.3 1.4
1992 2.1 2.2 2.3 2.4
select year, (select amount from a a1 where a1.year=a.year and month=1 ) as m1, (select amount from a a1 where a1.year=a.year and month=2) as m2, (select amount from a a1 where a1.year=a.year and month=3) as m3, (select amount from a a1 where a1.year=a.year and month=4) as m4 from a group by year
7.有两张表A和B,均有key和value两个字段,如果B的key在A中也有,那么把B的value换为A中对应的value。
#oracle update B set B.value=( select A.value from A where B.mykey=A.mykey ) where B.mykey in ( select B.mykey from B,A where B.mykey=A.mykey );
#mysql update B set value=( select A.value from A where A.mykey = B.mykey ) where mykey in ( select temp.mykey from (select B.* from B,A where B.mykey=A.mykey) as temp );