牛客 - 计算糖果(java)

题目

在这里插入图片描述

解题思路

这就是个计算题,A ,B, C三人的糖果我们都不知道,但根据他给的示例可以得出这样的结果:
1: (A - B) +(A + B) = 2A;
2: (B + C) - (B - C) = 2C;
3: (B - C) + (B + C) = 2B;
4: (A + B) - (A - B) = 2B;
3 和 4就可以判断出是否存在这样的整数了

解题代码

import java.util.*;
public class Main{
    
    
    public static void main(String[] args){
    
    
        Scanner scan = new Scanner(System.in);
        int a = scan.nextInt();
        int b = scan.nextInt();
        int c = scan.nextInt();
        int d = scan.nextInt();
        
        int A = (a + c) / 2;
        int C = (d - b) / 2;
        int B1 = (b + d) / 2;
        int B2 = (c - a) / 2;
        if(B1 != B2){
    
    
            System.out.println("No");
        }else{
    
    
            System.out.println(A+" "+B1+" "+C);
        }
        
    }
}

题链接

计算糖果链接

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转载自blog.csdn.net/chenbaifan/article/details/124633539