对象集合如何根据对象的某一个属性排序

1.Comparator对象进行排序

这种写法较为简单的1.8的写法,也可以在对象中重写排序方法以达到排序的功能,但是对代码要求较高

//按照List中对象的id属性升序

list.sort(Comparator.comparing(Person::getId))

//按照List中对象的id属性降序

list.sort(Comparator.comparing(Person::getId).reversed());

//多条件升序

list.sort(Comparator.comparing(Person::getId).thenComparing(Stu::getAge));

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//id降序
list.sort(Comparator.comparing(Person::getId).reversed().thenComparing(Stu::getAge))

例子如下

加入你需要排序的对象集合如下

创建了全局常量Person集合的全局常量PERSON_LIST,以共享使用

同时重写了构造器方法,方便在创建对象后,可以使用PERSON_LIST进行排序,不需要重复的撰写set方法来为对象集合添加测试数据

/**
 * @author wangli
 * @create 2022-08-27 15:35
 */
@Data
@ToString
public class Person {
    public final static List<Person> PERSON_LIST=new ArrayList<>();

    @Excel(name = "序号")
    private int id;

    @Excel(name = "名字")

    private String name;

    @Excel(name = "年纪")
    private Integer age;


    public Person() {
        Person person = new Person(3, "士大夫", 44);
        Person person1 = new Person(5, "彩色", 34);
        Person person2 = new Person(13, "设置", 31);
        Person person3 = new Person(1, "是的", 86);
        Person person4 = new Person(75, "衬衫", 47);
        Person person5 = new Person(75, "衬衫", 25);
        Person person6 = new Person(75, "衬衫", 98);
        PERSON_LIST.add(person);
        PERSON_LIST.add(person1);
        PERSON_LIST.add(person2);
        PERSON_LIST.add(person3);
        PERSON_LIST.add(person4);
        PERSON_LIST.add(person5);
        PERSON_LIST.add(person6);
    }

    public Person(int id, String name, Integer age) {
        this.id = id;
        this.name = name;
        this.age = age;
    }
}

 使用Comparator对对象集合排序。首先对id排序,若id一致,对age进行排序

/**
 * @author wangli
 * @create 2022-08-30 9:27
 */
public class TestJson {

    @Test
    public void ListSort(){
        Person person = new Person();
        PERSON_LIST.sort(Comparator.comparing(Person::getId).thenComparing(Comparator.comparing(Person::getAge)));
        for (Person person1 : PERSON_LIST) {
            System.out.println("person1 = " + person1);
        }

    }
}

运行得到结果如下,可见得到的结果是按id正序,同时id一致的情况下,按照age正序排序

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转载自blog.csdn.net/wang20010104/article/details/127314366