leetcode Majority Element

Majority Element

题目详情:

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

Credits:
Special thanks to @ts for adding this problem and creating all test cases.


解题方法:

这是一道非常经典的算法题,寻找众数。首先初始化一个result,和一个count都为0,分别用来存放结果和计数。当count为0时,result为nums[i],count+1,否则当result==nums[i]时count+1,result != nums[i]时,count-1,result即为想要的结果。


详细代码:

class Solution {
public:
    int majorityElement(vector<int>& nums) {
        int result = 0;
        int count = 0;
        for (int i = 0; i < nums.size(); i++) {
            if(count == 0)  {
                 result = nums[i];
                 count = 1;
             }
             else    {
                 if(result == nums[i])
                     count++;
                 else
                     count--;
             }
        }
        return result;
    }
};


复杂度分析:

时间复杂度为O(n),仅遍历了一次数组。

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转载自blog.csdn.net/weixin_40085482/article/details/78120720