代码随想录算法训练营第十四天| 递归遍历|迭代遍历|

递归遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
    
    
    void traversal(TreeNode* root,vector<int>&res){
    
    
        if(root==nullptr)
        return ;
        // traversal(root->left,res);
        res.push_back(root->val);
         traversal(root->left,res);
        traversal(root->right,res);
    }
public:
    vector<int> preorderTraversal(TreeNode* root) {
    
    
        vector<int>res;
        traversal(root,res);
        return res;
    }
};

迭代遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
    
    
public:
    vector<int> preorderTraversal(TreeNode* root) {
    
    
        vector<int>res;
        stack<TreeNode*>sta;
        if(root!=nullptr) sta.push(root);
            while(!sta.empty()){
    
    
            TreeNode *node=sta.top();
            sta.pop();
            res.push_back(node->val);
            if(node->right!=nullptr)sta.push(node->right);
            if(node->left!=nullptr)sta.push(node->left);
        }
        return res;
    }
};

统一风格迭代遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
    
    
public:
    vector<int> inorderTraversal(TreeNode* root) {
    
    
        stack<TreeNode*>sta;
         vector<int>res;
        if(root!=nullptr) sta.push(root);
        while(!sta.empty()){
    
    
            TreeNode*node=sta.top();
            if(node!=nullptr){
    
    
                sta.pop();
                if(node->right!=nullptr)sta.push(node->right);
                sta.push(node);
                sta.push(nullptr);
                if(node->left!=nullptr)sta.push(node->left);
            }else{
    
    
                sta.pop();
                node=sta.top();
                res.push_back(node->val);
                sta.pop();
            }
        }
        return res;
    }
};

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转载自blog.csdn.net/weixin_43541510/article/details/132175664