2023-09-02力扣每日一题

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2511. 最多可以摧毁的敌人城堡数目

题意和解

阅读理解题,要从1到-1或-1到1,中间只能有0,求最多能有多少0

实际代码:

#include<bits/stdc++.h>
using namespace std;
int captureForts(vector<int>& forts)
{
	int ans=0,after=1E8+7;
	bool Left=false;
	for(int i=0;i<forts.size();i++)
	{
		if(forts[i]==1)
		{
			if(!Left) ans=max(ans,i-after-1);
			after=i;Left=true;
		}
		else if(forts[i]==-1)
		{
			if(Left) ans=max(ans,i-after-1);
			after=i;Left=false;
		}
	}
	return ans>=0?ans:0;
}
int main()
{
	vector<int> forts;int fort;
	while(cin>>fort) forts.push_back(fort);
	int ans=captureForts(forts);
	cout<<ans<<endl;
	return 0;
}

限制:

  • 1 <= forts.length <= 1000
  • -1 <= forts[i] <= 1

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转载自blog.csdn.net/Fei_WuYan/article/details/132644126