Java解一元二次方程

import java.util.Scanner;

public class Calculate {
    public static void main(String[] args){
        //创建键盘录入
        Scanner sc=new Scanner(System.in);

        System.out.println("一元二次方程的运算");
        System.out.println("0=ax2+bx+c");
        System.out.println("求解x");

        System.out.println("请输入a:");
        double a=sc.nextDouble();

        System.out.println("请输入b:");
        double b=sc.nextDouble();

        System.out.println("请输入c:");
        double c=sc.nextDouble();

        //泽塔判断
        double dt= Math.pow(b,2)-4*a*c;

        if (dt == 0){
            System.out.println("此方程只有一个解");
            double x =(-b) /(2*a);
            System.out.println("解:");
            System.out.println("x="+x);
        }else if (dt > 0){
            System.out.println("此方程有两个解");
            double x1=(-b+Math.sqrt(dt)) /(2*a);
            double x2=(-b-Math.sqrt(dt)) /(2*a);
            System.out.println("解:");
            System.out.println("x1="+ x1);
            System.out.println("x2="+ x2);
        }else{
            System.out.println("此方程无解");
        }
    }
}

猜你喜欢

转载自blog.csdn.net/2301_78218192/article/details/132489755