题目：
修改以下程序，使其使用两个名为SumArray()的模板函数来返回数组元素的总和，而不是显示数组的内容。程序应显示thing的总和以及所有debt的总和
#include <iostream>
template <typename T>
void ShowArray(T arr[], int n);
template <typename T>
void ShowArray(T* arr[], int n);
struct debts
{
char name[50];
double amount;
};
int main()
{
using namespace std;
int things[6] = { 13,31,103,301,310,130 };
struct debts mr_E[3] =
{
{"Tma Wolfe",2400.0},
{"Ura Foxe",1300.0},
{"Iby Stout",1800.0}
};
double* pd[3];
for (int i = 0; i < 3; i++)
{
pd[i] = &mr_E[i].amount;
}
cout << "Listing Mr.E's counts of things:\n";
ShowArray(things, 6);
cout << "Listing Mr.E's debts:\n";
ShowArray(pd, 3);
return 0;
}
template <typename T>
void ShowArray(T arr[], int n)
{
using namespace std;
cout << "template A\n";
for (int i = 0; i < n; i++)
cout << arr[i] << ' ';
cout << endl;
}
template <typename T>
void ShowArray(T* arr[], int n)
{
using namespace std;
cout << "template B\n";
for (int i = 0; i < n; i++)
cout << *arr[i] << ' ';
cout << endl;
}
源代码：
#include <iostream>
struct debts
{
char name[50];
double amount;
};
template <typename T>
float SumArray(T arr[], int n);
template <>float SumArray(debts arr[], int n);
int main()
{
using namespace std;
int things[6] = { 13,31,103,301,310,130 };
struct debts mr_E[3] =
{
{"Tma Wolfe",2400.2},
{"Ura Foxe",1300.3},
{"Iby Stout",1800.0}
};
cout << "things 总和: " << SumArray(things, 6) << endl;
cout << "debt总和: " << SumArray(mr_E, 3);
return 0;
}
template <typename T>
float SumArray(T arr[], int n)
{
int total = 0;
for (int i = 0; i < n; i++)
{
total = total + arr[i];
}
return total;
}
template <> float SumArray(debts arr[], int n)
{
double total = 0;
for (int i = 0; i < n; i++)
{
total = total + arr[i].amount;
}
return total;
}
演示效果：
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