python练习 - 2

输入某年某月某日,判断这一天是这一年的第几天?
year = int(input('year:'))
month = int(input('month:'))
day = int(input('day:'))
#定义闰年的字典
month_dict1 = {'1': 31, '2': 28, '3': 31, '4': 30, '5': 31, '6': 30, '7': 31,
              '8': 31, '9': 30, '10': 31, '11': 30, '12': 31}
#定义平年的字典
month_dict2 = {'1': 31, '2': 29, '3': 31, '4': 30, '5': 31, '6': 30, '7': 31,
              '8': 31, '9': 30, '10': 31, '11': 30, '12': 31}
days = 0
if year % 400 == 0 or (year % 4 == 0 and year % 100 != 0):
    month_dict = month_dict2

    for i in range(1, month):
        days += month_dict[str(i)]
    days += day
else:
    month_dict = month_dict1
    for i in range(1, month):
        days += month_dict[str(i)]
    days += day

print(days)
结果:
year:2018
month:3
day:22
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转载自blog.csdn.net/jiayangwu/article/details/79661641
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