【JS】找出两个数组中的相同元素与不同元素

一、找出相同元素

(1)方法一

const filterArr = (arr1, arr2) => {
    
    
  let result = [];
  for (let i = 0; i < arr1.length; i++) {
    
    
    for (let j = 0; j < arr2.length; j++) {
    
    
      if (arr1[i] === arr2[j]) {
    
    
        result.push(arr1[i]);
      }
    }
  }
  return result;
};

(2)方法二

const filterArr = (arr1, arr2) => {
    
    
  return arr1.filter((t) => {
    
    
    return arr2.includes(t);
  });
};

(3)方法三

const filterArr = (arr1, arr2) => {
    
    
  return arr1.filter((t) => {
    
    
    return arr2.indexOf(t) !== -1;
  });
};
一、找出不同元素

(1)方法一

const filterArr = (arr1, arr2) => {
    
    
  const arr = [...arr1, ...arr2];
  const newArr = arr.filter((t) => {
    
    
    return !(arr1.includes(t) && arr2.includes(t));
  });
  return newArr;
};

(2)方法二

const filterArr2 = (arr1, arr2) => {
    
    
  return arr1.concat(arr2).filter((t, i, arr) => {
    
    
    return arr.indexOf(t) === arr.lastIndexOf(t);
  });
};

(3)方法三

const arr1 = A.filter((t) => !B.includes(t));
const arr2 = B.filter((x) => !A.includes(x));
const newArr = arr1.concat(arr2);

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转载自blog.csdn.net/m0_46613429/article/details/129693963