为了生成 NvD3 图表，需要将具有一个结构的 JSON 数据转换为另一个结构。尽管已在过去的几天中一直在寻求和阅读解决方案，我只能获得部分解决方案。该解决方案有效，但只要向 data_json 字典添加一个键/值对，它就会停止运行。

最奇怪的是，尽管引用 datos_TEU 的行已注释掉，但它仍然会为该字典条目分配值，并且不知道为什么。即使只取消注释第一个循环，它最终也会与另一个键具有相同的数据。所以我最终得到 2 份相同的数据，插入在 2 个不同的键中。除此之外，它还在循环中重复数据或产生“重叠”。

我肯定犯了一个很大的新手错误，但我看不到它。我已经尝试在整个早上和下午打印所有内容到 shell 并尝试不同的方法，但我无法发现错误。

data = json.load(url_obj)
tarifas = ('2.0A','2.0DHA','2.0DHSA')
fecha = '12345' #Just to develop
terminos = ('Dia','Hora','GEN','NOC','VHC','COFGEN','COFNOC','COFVHC','PMHGEN','PMHNOC','PMHVHC','SAHGEN','SAHNOC','SAHVHC','FOMGEN','FOMNOC','FOMVHC','FOSGEN','FOSNOC','FOSVHC','INTGEN','INTNOC','INTVHC','PCAPGEN','PCAPNOC','PCAPVHC','TEUGEN','TEUNOC','TEUVHC')


data_json = {
    
    'datos_TOT':[],'datos_TEU':[],'Fecha':fecha}

for i,tarifa in enumerate(tarifas):
    tarifas_dicc= {
    
    'tarifa':tarifa}
    tarifas_dicc['data'] = [] #Clean and create a new empty one.
    data_json['datos_TOT'].append(tarifas_dicc)
=>  #data_json['datos_TEU'].append(tarifas_dicc) I found that problems start when I uncomment this line. From here on the returned data will have duplicities or data that should´nt be there.
    list_terminos = terminos[(2+i)::3] #The original data is coded in a single dictionary and I have to split it into 3 different categories.


    for j in range (0,3):
        periodo_dicc = {
    
    'periodo':'{0}-{1}'.format(j,j+1)}
        periodo_dicc['data'] = [] #Clean and create a new empty one.
        #data_json['datos_TEU'][i]['data'].append(periodo_dicc)
        data_json['datos_TOT'][i]['data'].append(periodo_dicc)

        for k,termino in enumerate(list_terminos):
            data_dicc_TOT = {
    
    'value':data["PVPC"][j][termino]} #This structure come from the original data_json i´m using

            data_dicc_TOT['label'] = termino
            #data_dicc_TEU = {
    
    'value':data["PVPC"][j][list_terminos[0]]}
            #data_dicc_TEU['label'] = list_terminos[0]
            #data_json['datos_TEU'][i]['data'][j]['data'].append(data_dicc_TEU)
            data_json['datos_TOT'][i]['data'][j]['data'].append(data_dicc_TOT)

Where am I assigning the data to the other key?

2、解决方案

错误在于 data_json['datos_TOT'][i]['data'].append(periodo_dicc) 和 data_json['datos_TOT'][i]['data'][j]['data'].append(data_dicc_TOT)。当取消注释 data_json['datos_TEU'].append(tarifas_dicc) 时，它将 tarifas_dicc 添加到 data_json['datos_TEU'] 中，即使 data_json['datos_TEU'][i]['data'].append(periodo_dicc) 和 data_json['datos_TOT'][i]['data'][j]['data'].append(data_dicc_TOT) 将数据添加到 data_json['datos_TOT'] 中。

要修复这个问题，需要将 data_json['datos_TEU'].append(tarifas_dicc) 取消注释，然后将 data_json['datos_TOT'][i]['data'].append(periodo_dicc) 和 data_json['datos_TOT'][i]['data'][j]['data'].append(data_dicc_TOT) 注释掉。

data = json.load(url_obj)
tarifas = ('2.0A','2.0DHA','2.0DHSA')
fecha = '12345' #Just to develop
terminos = ('Dia','Hora','GEN','NOC','VHC','COFGEN','COFNOC','COFVHC','PMHGEN','PMHNOC','PMHVHC','SAHGEN','SAHNOC','SAHVHC','FOMGEN','FOMNOC','FOMVHC','FOSGEN','FOSNOC','FOSVHC','INTGEN','INTNOC','INTVHC','PCAPGEN','PCAPNOC','PCAPVHC','TEUGEN','TEUNOC','TEUVHC')


data_json = {
    
    'datos_TOT':[],'datos_TEU':[],'Fecha':fecha}

for i,tarifa in enumerate(tarifas):
    tarifas_dicc= {
    
    'tarifa':tarifa}
    tarifas_dicc['data'] = [] #Clean and create a new empty one.
    data_json['datos_TOT'].append(tarifas_dicc)
    data_json['datos_TEU'].append(tarifas_dicc) # Uncomment this line.
    list_terminos = terminos[(2+i)::3] #The original data is coded in a single dictionary and I have to split it into 3 different categories.


    for j in range (0,3):
        periodo_dicc = {
    
    'periodo':'{0}-{1}'.format(j,j+1)}
        periodo_dicc['data'] = [] #Clean and create a new empty one.
        #data_json['datos_TEU'][i]['data'].append(periodo_dicc) # Comment this line.
        #data_json['datos_TOT'][i]['data'].append(periodo_dicc) # Comment this line.

        for k,termino in enumerate(list_terminos):
            data_dicc_TOT = {
    
    'value':data["PVPC"][j][termino]} #This structure come from the original data_json i´m using

            data_dicc_TOT['label'] = termino
            #data_dicc_TEU = {'value':data["PVPC"][j][list_terminos[0]]}
            #data_dicc_TEU['label'] = list_terminos[0]
            #data_json['datos_TEU'][i]['data'][j]['data'].append(data_dicc_TEU)
            #data_json['datos_TOT'][i]['data'][j]['data'].append(data_dicc_TOT) # Comment this line.