目录
创建空元组
tup1 = ()
print(tup1) # ()
print(type(tup1)) # <class 'tuple'>元组中只有一个元素，一般要在元素后面加 逗号，
若不加，该数据类型不一定是元组，取决于元素的数据类型
tup2 = (12)
print(tup2) # 12
print(type(tup2)) # <class 'int'>
tup3 = ('hello')
print(tup3) # hello
print(type(tup3)) # <class 'str'>
tup4 = (12,)
print(tup4) # (12,)
print(type(tup4)) # <class 'tuple'>元组中的数据可以是不同的数据类型
tup5 = (1, 2, True, 'hello')
print(tup5) # (1, 2, True, 'hello')元组元素的访问
通过下标访问， 0下标表示第一个元素，-1下标表示最后一个元素
tup1 = (1, 2, True, 'hello')
print(tup5[0]) # 1
print(tup5[-1]) # hello元组中的元素不能修改
tup1 = (1, 2, True, 'hello')
tup1[0] = 9 # 报错 'tuple' object does not support item assignment
print(tup1)删除元组 del
tup1 = (1, 2, True, 'hello')
del tup1
print(tup1) # NameError: name 'tup1' is not defined. Did you mean: 'tup2'? 报错，因为tup1已将删除了，即没有定义就访问会报错
元组的合并、重复、判断
tup1 = (12, 25, 66, True, 'pig')
tup2 = (23, 11, 25, False, 'dog')
# 合并元组 +
print(tup1 + tup2) # (12, 25, 66, True, 'pig', 23, 11, 25, False, 'dog')
# 重复元组中的元素
print(tup1 * 2) # (12, 25, 66, True, 'pig', 12, 25, 66, True, 'pig')
# 判断元素是否在元组中， 使用成员运算符 in 和 not in
print(12 in tup1) # True
print(12 not in tup2) # True
元组的切片
tup1 = (12, 25, 66, True, 'pig', 23, 11, 25, False, 'dog')
print(tup1[1:5]) # (25, 66, True, 'pig')
print(tup1[2:]) # (66, True, 'pig', 23, 11, 25, False, 'dog')
print(tup1[:7]) # (12, 25, 66, True, 'pig', 23, 11)
print(tup1[-4:]) # (11, 25, False, 'dog')
print(tup1[::-1]) # ('dog', False, 25, 11, 23, 'pig', True, 66, 25, 12)获取元组的长度
tup1 = (12, 25, 66, 31, 90)
print(len(tup1)) # 5获取元组中的最大值和最小值
# 获取元组中的最大值
print(max(tup1)) # 90
# 获取元素中的最小值
print(min(tup1)) # 12将其他数据类型转换为元组 tuple()
list1 = [12, 34, 66, 24, True, 'hello']
print(list1) # [12, 34, 66, 24, True, 'hello']
print(tuple(list1)) # (12, 34, 66, 24, True, 'hello')
print(type(tuple(list1))) # <class 'tuple'>元组的遍历
tup1 = (12, 25, 66, 31, 90)
# 第一种方式
for i in tup1:
print(i)
# 第二种方式
for i in range(len(tup1)):
print(tup1[i])
# 第三种方式
for k, v in enumerate(tup1):
print(k, '========', v)多维元组
tup1 = (1, 2, 4, True, (6, 7, 8, (11, 12, 15)), 0, 3)
print(tup1[3]) # True
print(tup1[4][1]) # 7
print(tup1[4][3][1]) # 12