算法笔记：codeup 1928 日期差值

题目描述

有两个日期，求两个日期之间的天数，如果两个日期是连续的我们规定他们之间的天数为两天。

输入

有多组数据，每组数据有两行，分别表示两个日期，形式为YYYYMMDD

输出

每组数据输出一行，即日期差值

样例输入

20130101
20130105

样例输出

5

#include<cstdio>
int isleap(int Y){
	if(((Y%4==0)&&(Y%100!=0))||Y%400==0)return 1;
	else return 0;
}
int main(){
	int month[13][2]={
		{0,0},
		{31,31},
		{28,29},
		{31,31},
		{30,30},
		{31,31},
		{30,30},
		{31,31},
		{31,31},
		{30,30},
		{31,31},
		{30,30},
		{31,31}
	};
	int time_1,time_2;
	while(scanf("%d %d",&time_1,&time_2)!=EOF){
		int ans=1;
		if(time_1>time_2){
			int temp;
			temp=time_1;
			time_1=time_2;
			time_2=temp;
		}
		int Y_1,Y_2,M_1,M_2,D_1,D_2;
		Y_1=time_1/10000;
		Y_2=time_2/10000;
		M_1=(time_1%10000)/100;
		M_2=(time_2%10000)/100;
		D_1=(time_1%10000)%100;
		D_2=(time_2%10000)%100;
		while(!((Y_1==Y_2)&&(M_1==M_2)&&(D_1==D_2))){
			D_1++;
			ans++;
			if(D_1==month[M_1][isleap(Y_1)]+1){
				M_1++;
				D_1=1;
			}
			if(M_1==13){
				Y_1++;
				M_1=1;
			}
		}
		printf("%d\n",ans);
	}
	return 0;
}